Căn 25/4 - căn 49/16
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a: \(\dfrac{\sqrt{81}}{\sqrt{16}}=\dfrac{9}{4}=\dfrac{36}{16}< \dfrac{81}{16}\)
b: \(\sqrt{16+25}=\sqrt{41}< 9=\sqrt{16}+\sqrt{25}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$\sqrt{0,16}+\sqrt{\frac{4}{25}}=\sqrt{0,16}+\sqrt{0,16}$
$=2\sqrt{0,16}=2\sqrt{0,4^2}=2.0,4=0,8$
\(\sqrt{0.16}+\sqrt{\dfrac{4}{25}}\)
\(=0.4+\dfrac{2}{5}\)
=0.8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sqrt{16}=4\)
\(\sqrt{49}=7\)
\(\sqrt{121}=11\)
\(\sqrt{169}=13\)
\(\sqrt{196}=14\)
trả lời
\(\sqrt{16}\);\(\sqrt{49}\);\(\sqrt{121}\);\(\sqrt{169}\);\(\sqrt{196}\)
chúc bn hok tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5\sqrt{16}-4\sqrt{9}+\sqrt{25}-0,3\sqrt{400}\)
\(=20-12+5-6\)
\(=7\)
Ý của bạn là \(\left(5\sqrt{16}\right)-\left(4\sqrt{9}\right)+\left(\sqrt{25}\right)-\left(0,3\sqrt{400}\right)\)phải k???
\(\left(5\sqrt{16}\right)-\left(4\sqrt{9}\right)+\left(\sqrt{25}\right)-\left(0,3\sqrt{400}\right)\)
\(=\left(5.4\right)-\left(4.3\right)+5-\left(0,3.20\right)\\ =20-12+5-6\\ =8+5-6\\ =13-6\\ =7\)
Chúc các bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(4-\sqrt{x^2+1}-2\sqrt{16\left(x^2+1\right)}+5\sqrt{25\left(x^2+1\right)}\)
\(=4-\sqrt{x^2+1}-4\sqrt{x^2+1}+25\sqrt{x^2+1}\)
\(=20\sqrt{x^2+1}+4\)
\(\sqrt{\dfrac{25}{4}}-\sqrt{\dfrac{49}{16}}=\dfrac{5}{2}-\dfrac{7}{4}=\dfrac{10}{4}-\dfrac{7}{4}=\dfrac{3}{4}\)
căn 25/4-căn 49/16=căn(5/2)mũ 2-căn(7/4)mũ 2=5/2-7/4=3/4