(3x-2)\(^{^2}\)=2.2\(^{^3}\)
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\(\sqrt{x^2+3x+3}=1\)
\(\Leftrightarrow x^2+3x+3=1\)
\(\Leftrightarrow x^2+3x+2=0\)
\(\Leftrightarrow x^2+x+2x+2=0\)
\(\Leftrightarrow x\left(x+1\right)+2\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+2=0\\x+1=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-2\\x=-1\end{cases}}\)
\(2\sqrt{x+2+2\sqrt{x+1}}-\sqrt{x+1}=4\)
\(\Leftrightarrow2\sqrt{x+1+2\sqrt{x+1}+1}-\sqrt{x+1}=4\)
\(\Leftrightarrow2\sqrt{\left(\sqrt{x+1}+1\right)^2}-\sqrt{x+1}=4\)
\(\Leftrightarrow2\left(\sqrt{x+1}+1\right)-\sqrt{x+1}=4\)
\(\Leftrightarrow2\sqrt{x+1}+2-\sqrt{x+1}=4\)
\(\Leftrightarrow\sqrt{x+1}=2\)
\(\Leftrightarrow x+1=4\)
\(\Leftrightarrow x=3\)
b) \(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
\(\Rightarrow\left(x+\frac{1}{2}\right)^2=\left(\pm\frac{1}{4}\right)^2\)
\(\Rightarrow x+\frac{1}{2}=\pm\frac{1}{4}.\)
\(\Rightarrow\left[{}\begin{matrix}x+\frac{1}{2}=\frac{1}{4}\\x+\frac{1}{2}=-\frac{1}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{1}{4}-\frac{1}{2}\\x=\left(-\frac{1}{4}\right)-\frac{1}{2}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\frac{1}{4}\\x=-\frac{3}{4}\end{matrix}\right.\)
Vậy \(x\in\left\{-\frac{1}{4};-\frac{3}{4}\right\}.\)
c) \(\left(3x+2\right)^3=-27\)
\(\Rightarrow\left(3x+2\right)^3=\left(-3\right)^3\)
\(\Rightarrow3x+2=-3\)
\(\Rightarrow3x=\left(-3\right)-2\)
\(\Rightarrow3x=-5\)
\(\Rightarrow x=\left(-5\right):3\)
\(\Rightarrow x=-\frac{5}{3}\)
Vậy \(x=-\frac{5}{3}.\)
Chúc bạn học tốt!
1. 25 : 5,7 = 250/57
2. 30:2.8.4 = 480
3. 20:2^2.14= 70
4. 125:5^3.170= 170
5. 64:2^5.30.4=240
6. (25:5^2.30): 15.7=14
bạn à! Nhiều quá mình ko làm hết được. sorry nha.^-^
\(3^2.2^4-2^3.4^2-2^3.5^0+4^2.2^2\)
\(=9.16-8.16-8.1+16.4\)
\(=16.\left(9-8\right)-8+64\)
\(=16.1-8+64\)
\(=8+64\)
\(=72\)
\(C=2^0+2^1+2^2+2^3+2^0+2^1+2^2+2^3\)
\(=\left(2^0.2\right)+\left(2^1.2\right)+\left(2^2.2\right)+\left(2^3.2\right)\)
\(=2+4+8+16\)
\(=\left(2+8\right)+\left(4+16\right)\)
\(=10+20\)
\(=30\)
\(D=\left(2^0+2^1+2^2+2^3\right).2^0.2^1.2^2.2^3\)
\(=\left(1+2+4+8\right).1.2.4.8\)
\(=\left(8+2+4+1\right).1.2.4.8\)
\(=\left(10+4+1\right).1.2.4.8\)
\(=15.1.2.4.8\)
\(=\left(15.2\right).1.4.8\)
\(=30.1.4.8\)
\(=120.8\)
\(=960\)
(3x-2)2 = 2.23
<=> (3x-2)2 = 24
<=> (3x-2)2 = (22)2
<=> 3x-2 = 22 hoặc 3x-2 = -22
<=> 3x-2 = 4 hoặc 3x-2 = -4
<=> 3x = 6 hoặc 3x = -2
<=> x = 2 hoặc x = -2/3
cảm ơn bn