CÁC BẠN GIẢI GIÙM MÌNH NHA :
1,tính 1 cách hợp lí:
a, 25.(-7).4
b,33.(17-5)-17.(33-5)
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mk làm câu b phần 1 thui tại vì câu a phần 1 và 2 DLT làm đúng rồi
b)33.(17-5)-17.(33-5)
=33.17-33.5-17.33-17.5
=(33.17-17.33)-(33.5-17.5)
=0.(33.5-17.5)
=0
a)\(25\cdot\left(-7\right)\cdot4=25\cdot4\cdot\left(-7\right)\)
=\(\left(-7\right)\cdot100=-700\)
b)\(33\cdot\left(17-5\right)-17\cdot\left(33-5\right)\)
=\(33\cdot12-17\cdot28\)
=\(-80\)
2) \(\frac{3}{4}\)giờ =\(45\)phút
a) 18.17 - 3.6.7
= 18.17-18.7
=18.( 17 - 7 )
= 18 . 10
= 180
b) 54 - 6.( 17 + 9)
= 6.9 - 6 . 26
= 6.( 9 - 26 )
= 6 . ( - 17 )
= -102
c) 33.(17 - 5 ) - 17.(33-5)
= 33.17 - 33 .3 - 17.33 - 17 . 5
= 33.17 + ( -33 ) .3 + ( - 17) .33 + ( -17) .5
= 33.17 + ( - 17) . 33 + 33 . ( - 3) + ( -17 ) .5
= 33. [ 17 + ( -17 ) + ( - 3 )] + (-17) . 5
= 33 . ( - 3 ) + ( -17 ) .5
= -99 + ( - 85)
= -184
a) 18 . 17 - 3 . 6 . 7 b) 54 - 6 . ( 17 + 9 )
= 306 - 126 = 48 . 26
= 180 = 1248
,mk giúp đc từng đó nha
\(\frac{17}{33}.\frac{2}{5}+\frac{3}{5}.\frac{17}{33}-\frac{17}{33}\)
\(=\frac{17}{33}\times\frac{2}{5}+\frac{3}{5}\times\frac{17}{33}-\frac{17}{33}\times1\)
\(=\frac{17}{33}\times\left(\frac{2}{5}+\frac{3}{5}-1\right)\)
\(=\frac{17}{33}\times\left(1-1\right)\)
\(=\frac{17}{33}\times0=\frac{17}{33}\)
\(a,18.17-3.6.7\)
\(=18.17-18.7\)
\(=18.\left(17-7\right)\)
\(=18.10\)
\(=180\)
\(b,54-6.\left(17+9\right)\)
\(=54-6.17+6.9\)
\(=54-102+54\)
\(=\left(54+54\right)-102\)
\(=108-102\)
\(=6\)
\(c,33.\left(17-5\right)-17.\left(33-5\right)\)
\(=33.17-33.5-17.33-17.5\)
\(=\left(33.17-17.33\right)-\left[5\left(33-17\right)\right]\)
\(=0-5.16\)
\(=-80\)
33.(17 – 5) – 17.(33 -5)
= 33. 17 – 33.5 – 17.33 + 17.5
= (33.17 – 33. 17) + ( 17.5 – 33.5)
= 0 + 5.(17- 33)
= 5.(- 16) = -80
\(a.\)
\(\dfrac{27}{13}-\dfrac{106}{111}+-\dfrac{5}{111}=\dfrac{27}{13}-\dfrac{106}{111}-\dfrac{5}{111}=\dfrac{27}{13}-\left(\dfrac{106+6}{111}\right)=\dfrac{27}{13}-1=\dfrac{14}{13}\)
\(b.\)
\(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+1=\dfrac{23}{11}\)
\(c.\)
\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+-\dfrac{6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{25}{31}+\dfrac{6}{31}\right)=1-1=0\)
a) \(\dfrac{27}{13}-\dfrac{106}{111}+\dfrac{-5}{111}=\dfrac{27}{13}+\left(\dfrac{-106}{111}+\dfrac{-5}{111}\right)=\dfrac{27}{13}+-1=\dfrac{14}{13}\)
b) \(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\left(\dfrac{7}{19}+\dfrac{12}{19}\right)=\dfrac{12}{11}+1=\dfrac{23}{11}\)
c)\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{-25}{31}+\dfrac{-6}{31}\right)=1+-1=0\)
a) 12 + 13 + 14 - 15 - 16 - 17
= (12 - 15) + (13 - 16) + (14 - 17)
= (-3) + (-3) + (-3) = -9
b) (35 - 17) - (25 - 7 + 22)
= 35 - 17 - 25 + 7 - 22
= (35 - 25) - (17 - 7) - 22
= 10 - 10 - 22 = -22
a) \(25.\left(-7\right).4=\left(25.4\right).\left(-7\right)=100.\left(-7\right)=-700\)
b) \(33.\left(17-5\right)-17.\left(33-5\right)=33.17-33.5-17.33+17.5=5.\left(17-33\right)\)\(=5.\left(-16\right)=-80\)
25.(-7).4
=(25.4).(-7)
=100.(-7)
=-700