2x-x0=35:33
Helpp!!!
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Ta có:
\(Ư\left(35\right)=\left\{\pm1;\pm5;\pm7;\pm35\right\}\\ \Rightarrow\left(2x+1\right),\left(2y-3\right)\in\left\{\left(5,7\right);\left(7,5\right);\left(-5;-7\right);\left(-7,-5\right);\left(1;35\right);\left(35,1\right);\left(-1,-35\right);\left(-35,-1\right)\right\}\\ \Rightarrow\left(x,y\right)\in\left\{\left(2,5\right);\left(3,4\right);\left(-3,-2\right);\left(-4,-1\right);\left(0,19\right);\left(17,2\right);\left(-1,-16\right);\left(-18,1\right)\right\}\)
\(\dfrac{2x+19}{21}-\dfrac{2x+17}{23}=\dfrac{2x+7}{33}-\dfrac{2x+5}{35}\)
\(\Rightarrow\dfrac{2x+19}{21}-\dfrac{2x+17}{23}-\dfrac{2x+7}{33}+\dfrac{2x+5}{35}=0\)
\(\Rightarrow\left(\dfrac{2x+19}{21}+1\right)-\left(\dfrac{2x+17}{23}+1\right)-\left(\dfrac{2x+7}{33}+1\right)+\left(\dfrac{2x+5}{35}+1\right)=0\)
\(\Rightarrow\dfrac{2x+40}{21}-\dfrac{2x+40}{23}-\dfrac{2x+40}{33}+\dfrac{2x+40}{35}=0\)
\(\Rightarrow\left(2x+40\right)\left(\dfrac{1}{21}-\dfrac{1}{23}-\dfrac{1}{33}+\dfrac{1}{35}\right)=0\)
\(\Rightarrow2x+40=0\Rightarrow x=-20\)( do \(\dfrac{1}{21}-\dfrac{1}{23}-\dfrac{1}{33}+\dfrac{1}{35}>0\))
Ta có: \(\dfrac{2x+19}{21}-\dfrac{2x+17}{23}=\dfrac{2x+7}{33}-\dfrac{2x+5}{35}\)
\(\Leftrightarrow\left(2x+40\right)\left(\dfrac{1}{21}-\dfrac{1}{23}-\dfrac{1}{33}+\dfrac{1}{35}\right)=0\)
\(\Leftrightarrow2x+40=0\)
hay x=-20
\(\left(35+x\right)-12=27\\ 35+x=27+12=39\\ x=39-35=4\\ ---\\ 2x-5=3^3:3^2=3\\ 2x=3+5=8\\ x=\dfrac{8}{2}=4\)
1) (35 + x) -12 =27
=>35 + x = 39 => x = 4
2) 2x -5 = 33 : 32
=> 2x -5 =31 => 2x = 8
=> x = 4
a, 2 3 x + 5 2 x = 2 5 2 + 2 3 - 33
8x+25x = 33
33x = 33
x = 1
b, 260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2
260:(x+4) = 5.13–3.13
x+4 = 260:26
x+4 = 10
x = 6
c, 720 : [ 41 - 2 x - 5 ] = 2 3 . 5
41–(2x–5) = 720:40
2x–5 = 41–18
2x = 28
x = 14
d, 3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2
7(x–12)+35 = 56
7(x–12) = 21
x–12 = 3
x = 15
a, 4x+18:2 = 13
4x+9 = 13
x = 1
b, 48 – 3(x+5) = 24
3(x+5) = 24
x + 5 = 8
x = 3
c, 2 x - 2 0 = 3 5 : 3 3
2x – 1 = 3 2
2x = 10
x = 5
d, (15+x):3 = 3 15 : 3 12
(15+x):3 = 3 3
(15+x):3 = 27
15 + x = 54
x = 39
2x-x0=35:33=32=9
=>2x-1=9
=>2x=9+1=10
=>x=10:2=5.
\(2x-x^0=3^5:3^3\\ 2x-1=3^{5-3}\\ 2x-1=3^2\\ 2x-1=9\\ 2x=9+1\\ 2x=10\\ x=\dfrac{10}{2}\\ x=5\)