1. Tính
a) (9/4)^5 : (1/4)^5
b) 18^2 : 9^2
c) [(-2)^4]^3
d) 5^7 . (1/5)^7
e) (6,5)^3 : (6,5)^2
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a, 2 -|3/2x -1/4| =|-1,25 |
=>2 -|3/2x-1/4 | = 1,25
=> |3/2x -1/4| = 2-1,25
=> 3/2x -1/4 = 0,75 hoac 3/2x -1/4 = -0,75
=> 3/2 x = 3/4 -1/4 hoac 3/2 x = -3/4 -1/4
=> 3/2 x = 1/2 hoac 3/2 x = -1
=> x = 1/2 :3/2 hoac x = -1 : 3/2
=> x = 1/3 hoac x = -2/3
vay
cảm ơn nhé nhưng mk bt làm òi
mk chỉ đăng câu hỏi cho vv thui
a: \(=\left(15-6-\dfrac{13}{18}\right):\dfrac{298}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{298}-\dfrac{5}{3}=\dfrac{3}{2}-\dfrac{5}{3}=\dfrac{9-10}{6}=\dfrac{-1}{6}\)
b: \(=\dfrac{-16}{5}\cdot\dfrac{-15}{64}+\dfrac{-22}{15}:\dfrac{11}{2}\)
\(=\dfrac{3}{4}-\dfrac{4}{15}=\dfrac{29}{60}\)
c: \(=\dfrac{-7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+5+\dfrac{7}{9}=\dfrac{-7}{9}+\dfrac{7}{9}+5=5\)
d: \(=\dfrac{1}{2}\cdot\dfrac{4}{3}\cdot10\cdot\dfrac{1}{5}\cdot\dfrac{3}{4}=1\)
e: \(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}+\dfrac{-23}{4}=\dfrac{204}{25}\)
a: =91/105+60/105-101/105
=50/105=10/21
c: \(\dfrac{3}{4}\cdot\dfrac{5}{2}\cdot\dfrac{7}{6}=\dfrac{3}{6}\cdot\dfrac{7}{2}\cdot\dfrac{5}{4}=\dfrac{1}{2}\cdot\dfrac{7}{2}\cdot\dfrac{5}{4}=\dfrac{35}{16}\)
d: =2-2/9
=18/9-2/9
=16/9
e: =24/36-9/36+8/36
=23/36
g: =5/2+1/2
=3
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18
a, (\(\dfrac{9}{4}\))5 : (\(\dfrac{1}{4}\))5
= (\(\dfrac{9}{4}\) : \(\dfrac{1}{4}\))5
= 95
= 59049
b, 182 : 92
= (18:9)2
= 22
= 4
c, [(-2)\(^4\)]3
= 212
= 4096
d, 57.(\(\dfrac{1}{5}\))7
= (5.\(\dfrac{1}{5}\))7
= 17
= 1
e, (6,5)3: (6,5)2
= 6,5