Question

[Thảo NGUYÊN]

Viêt kq của các biểu thức sau dưới dạng lũy thừa

Answer 1

[Nguyễn Lê Phước Thịnh]

d: =5^10*5^4/5^12=5^2

e: \(=\dfrac{2^{19}\cdot3^9+3^9\cdot2^{18}\cdot5}{2^{19}\cdot3^9+3^{10}\cdot2^{20}}\)

\(=\dfrac{2^{18}\cdot3^9\left(2+5\right)}{2^{19}\cdot3^9\left(1+3\cdot2\right)}=\dfrac{1}{2}\)

Answer 2

[『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』]

`@` `\text {Ans}`

`\downarrow`

`d)`

\(\dfrac{5^{10}\cdot25^2}{125^4}\)

`=`\(\dfrac{5^{10}\cdot\left(5^2\right)^2}{\left(5^3\right)^4}=\dfrac{5^{10}\cdot5^4}{5^{12}}=\dfrac{5^{14}}{5^{12}}=5^2\)

`e)`

\(\dfrac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)

`=`\(\dfrac{2^{19}\cdot3^9+3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot3^9\cdot2^{10}+2^{20}\cdot3^{10}}\)

`=`\(\dfrac{2^{19}\cdot3^9+5\cdot2^{18}\cdot3^9}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}\)

`=`\(\dfrac{2^{18}\cdot3^9\left(2+5\right)}{2^{19}\cdot3^9\left(1+2\cdot3\right)}\)

`=`\(\dfrac{2^{18}\cdot3^9}{2^{19}\cdot3^9}=\dfrac{1}{2}\)