3/1/3x+ 16/3/4= -13,25
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\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Rightarrow\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\)
\(\Rightarrow\dfrac{10}{3}x=\dfrac{-120}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-30\)
\(\Rightarrow x=-30:\dfrac{10}{3}\)
\(\Rightarrow x=-9\)
Vậy: ...
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Leftrightarrow\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)
\(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{10}{3}x=\dfrac{-120}{4}=-30\)
\(x=-30.\dfrac{3}{10}\)
\(x=\dfrac{-90}{10}=-9\)
Đề bài thế này đúng ko: 3. 1/3y + 16. 3/4 = -13,25
10/3 y + 67/4= -1325/100
10/3y= -1325/100 - 1675/100
10/3y = -3000/100
10/3y = 30
y= 30 : 10/3
y=9
10/3y+67/4=-1325/100
10/3y=-1235/100-67/4
10/3y=-30
y=-30:10/3
y=-9
Vậyy=-9
a) (7x - 11)3 = 25.52 + 200
(7x - 11)3 = 32.25 + 200
(7x - 11)3 = 800 + 200
(7x - 11)3 = 1000 = 103
=> 7x - 11 = 10
=> 7x = 10 + 11 = 21
=> x = 21 : 7 = 3
b) \(1\frac{1}{3}x+16\frac{3}{4}=-13,25\)
=> \(\frac{4}{3}x+\frac{67}{4}=-\frac{53}{4}\)
=> \(\frac{4}{3}x=-\frac{53}{4}-\frac{67}{4}\)
=> \(\frac{4}{3}x=-30\)
=> \(x=-30:\frac{4}{3}\)
=> \(x=-30.\frac{3}{4}=-\frac{45}{2}\)
\(1\frac{1}{3}\cdot x+16\frac{3}{4}=13,25\)
\(\frac{4}{3}\cdot x=13,25-16\frac{3}{4}\)
\(\frac{4}{3}\cdot x=-3,5\)
\(x=-3,5:\frac{4}{3}\)
\(x=-2,625\)
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(=>\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)
\(\frac{10}{3}x=-30\)
x = -30 : \(\frac{10}{3}\)
= > x = -9
a) \(x-\dfrac{5}{6}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{5}{6}\)
\(x=\dfrac{4}{3}\)
vậy x = ....
b) \(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\dfrac{10}{3}\)\(x+\dfrac{67}{4}=-13,25\)
\(\dfrac{10}{3}x=\left(-13,25\right)-\dfrac{67}{4}\)
\(\dfrac{10}{3}x=-30\)
\(x=\left(-30\right):\dfrac{10}{3}\)
\(x=-9\)
vậy x =...
sai mog bn thông cảm!!!
4/16 và 3/4