(x-22)3=2
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3/22 x 3/11 x 22=
c1:\(\frac{3\times3\times22}{22\times11}=\frac{9}{11}\) c2:\(\frac{9}{242}\times22=\frac{9}{11}\)
( 1/2 + 1/3 ) x 2/5=
c1:\(\frac{5}{6}\times\frac{2}{5}=\frac{1}{3}\) c2:\(\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}=\frac{1}{5}+\frac{2}{15}=\frac{1}{3}\)
\(\frac{3}{22}\times\frac{3}{11}\times22\)
1.\(=\frac{3\times3\times22}{22\times11\times1}\)
\(=\frac{3\times3}{11\times1}\)
\(=\frac{9}{11}\)
2. \(=\frac{9}{242}\times22\)
\(=\frac{198}{242}\)
\(=\frac{9\times2\times11}{2\times11\times11}\)
\(=\frac{9}{11}\)
\(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}\)
1.\(=\frac{5}{6}\times\frac{2}{5}\)
\(=\frac{5\times2}{3\times2\times5}\)
\(=\frac{1}{3}\)
2.\(\)\(=\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}\)
\(=\frac{1}{5}+\frac{2}{15}\)
\(=\frac{3}{15}+\frac{2}{15}\)
\(=\frac{5}{15}=\frac{1}{3}\)
Have a good day
Ta có: (x + 2)2 – 4 ≥ (x + 3)(x + 5) – x
⇔ x2 + 4x + 4 – 4 ≥ x2 + 5x + 3x + 15 – x
⇔ –3x ≥ 15 ⇔ x ≤ –5
Tập nghiệm: S = {x | x ≤ –5}.
Đặt \(A=\sqrt[3]{22\sqrt{2}+25}-\sqrt[3]{22\sqrt{2}-25}\)
\(\Rightarrow A^3=50-3\sqrt[3]{\left(22\sqrt{2}+25\right)\left(22\sqrt{2}-25\right)}\left(\sqrt[3]{22\sqrt{2}+25}-\sqrt[3]{22\sqrt{2}-25}\right)\)
\(\Rightarrow A^3=50-3\sqrt[3]{\left(22\sqrt{2}+25\right)\left(22\sqrt{2}-25\right)}\cdot A\)
\(\Rightarrow A^3=50-3A\sqrt[3]{343}=50-21A\)
\(\Rightarrow A^3+21A-50=0\Leftrightarrow A^3-4A+25A-50=0\)
\(\Leftrightarrow\left(A-2\right)\left(A^2+2A+25\right)=0\)
\(\Leftrightarrow A=2\left(A^2+2A+25>0,\forall A\right)\)
\(\Rightarrow\sqrt[3]{22\sqrt{2}+25}-\sqrt[3]{22\sqrt{2}-25}=2\)
Tick nha bạn 😘
1, =4/9 x (3/7 + 2 x 4/7) - 1/9 - 3/9
= 4/9 x 1 - 1/9 - 3/9 = 0
2, = ( 22/5 x 5/22 ) x 12
= 1 x 12 = 12
a: \(=\dfrac{3}{5}:\dfrac{7}{5}=\dfrac{3}{5}\cdot\dfrac{5}{7}=\dfrac{3}{7}\)
b: \(=\dfrac{9}{17}\left(\dfrac{8}{5}-\dfrac{3}{5}\right)+\dfrac{8}{17}\)
=9/17+8/17=1
c: =>x-3/10=7/15*1/5=7/75
=>x=7/75+3/10=59/150
a, \(\frac{2}{3}\)x \(\frac{10}{21}\)x \(\frac{3}{2}\)= \(\frac{2x10x3}{3x21x2}\) = \(\frac{10}{21}\)
b, \(\frac{22}{5}\)x \(12\)x\(\frac{5}{22}\) = \(\frac{22x12x5}{5x22}\) = \(12\)
TA CÓ ( X -4 ) ^ 3 = 2
=> X KHÔNG CÓ GIÁ TRỊ THỎA MNAX VÌ KHÔNG CÓ
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