44 + 7 nhân x =10 mũ̃ 3 :10
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44 + 7 . x = 103 : 10
44 + 7 . x = 100
7 . x = 100 - 44
7 . x = 56
x = 56 : 7
x = 8
Vậy x bằng 8
A) 5/4 x X = 3/8 + 5/12
5/4 x X = 19/24
X = 19/24 : 5/4
X = 19/30
vậy x =...
B, 3 x 7/10 + 7/10 x 5 + 2 x 7/10
= 7/10 x ( 3 + 5 + 2)
= 7/10 x 10
= 7
\(3\cdot\left(\dfrac{1}{2}-x\right)-5\left(x-\dfrac{1}{10}\right)=-\dfrac{7}{4}\\ \Leftrightarrow-8x=-\dfrac{15}{4}\\ \Leftrightarrow x=\dfrac{15}{32}\)
\(4\left(\dfrac{3}{4}+x\right)-\dfrac{1}{5}=7x-\dfrac{1}{7}\\ \Leftrightarrow3x=\dfrac{103}{35}\\ \Leftrightarrow x=\dfrac{103}{105}\)
\(3\left(\dfrac{1}{2}-x\right)-5\left(x-\dfrac{1}{10}\right)=-\dfrac{7}{4}\)
\(\Rightarrow\dfrac{3}{2}-3x-5x+\dfrac{1}{2}=-\dfrac{7}{4}\)
\(\Rightarrow2-8x=-\dfrac{7}{4}\)
\(\Rightarrow8x=2+\dfrac{7}{4}\)
\(\Rightarrow8x=\dfrac{15}{4}\)
\(\Rightarrow x=\dfrac{15}{32}\)
___________
\(4\left(\dfrac{3}{4}+x\right)-\dfrac{1}{5}=7x-\dfrac{1}{7}\)
\(\Rightarrow3+4x-\dfrac{1}{5}=7x-\dfrac{1}{7}\)
\(\Rightarrow4x+\dfrac{14}{5}=7x-\dfrac{1}{7}\)
\(\Rightarrow7x-4x=\dfrac{14}{5}+\dfrac{1}{7}\)
\(\Rightarrow3x=\dfrac{103}{35}\)
\(\Rightarrow x=\dfrac{103}{105}\)
a) \(27^{15}=\left(3^3\right)^{15}=3^{45}\)
\(81^{11}=\left(3^4\right)^{11}=3^{44}\)
vì 344 < 345 nên 8111 < 2715
Cái dề, bài này giúp á, tính ra là ok mà
(13/10x - 15).(-5/14) = 3
13/10x - 15 = 3 : (-5/14)
13/10x - 15 = 3 x (-14/5)
13/10x - 15 = -42/5
=> 13/10x = -42/5 + 15
=> 13/10x = 33/5
=> x = 33/5 : 13/10
=> x = 33/5 x 10/13
=> x = 66/13
bn tự lm típ, tính ra là ok mà
44 \(\times\) 5 + 18 \(\times\) 10 + 20 \(\times\) 5
= 44 \(\times\) 5 + 18 \(\times\) 2 \(\times\) 5 + 20 \(\times\) 5
= 44 \(\times\) 5 + 36 \(\times\) 5 + 20 \(\times\) 5
= 5 \(\times\) ( 44 + 36 + 20)
= 5 \(\times\) 100
= 500
\(\frac{10}{3}.x+\frac{67}{4}=\frac{53}{4}\)
\(\frac{10}{3}.x=\frac{53}{4}-\frac{67}{4}\)
\(\frac{10}{3}.x=-\frac{7}{2}\)
\(x=-\frac{7}{2}:\frac{10}{3}\)
\(x=-\frac{21}{20}\)
44+7.x=10^3:10
44+7.x=1000:10
44+7.x=100
7x=100-44
7x=56
x=56:7
x=8
vậy x=8