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15 tháng 7 2022

\(45:\dfrac{7}{18}+50%-1,25\)

\(=45. \dfrac{18}{7}+\dfrac{1}{2}-\dfrac{5}{4}\)

\(=\dfrac{810}{7}+\dfrac{1}{2}-\dfrac{5}{4}\)

\(=\dfrac{1627}{14}-\dfrac{5}{4}\)

\(=\dfrac{3219}{28}\)

15 tháng 7 2022

   45: \(\dfrac{7}{18}\) + 50% - 1,25

= 45 x \(\dfrac{18}{7}\) + \(\dfrac{50}{100}\) - \(\dfrac{125}{100}\)

   =   \(\dfrac{810}{7}\)\(\dfrac{75}{100}\)

\(\dfrac{81000}{700}\) - \(\dfrac{525}{700}\)

=\(\dfrac{80475}{700}\)

=\(\dfrac{3219}{28}\)

`= -45 \div 18/7-0,5+1,25`

`= -17,5-0,5+1,25`

`= -18+1,25=-16,75`

14 tháng 4 2018

Giải:

a) \(25\%-\dfrac{5}{4}+\dfrac{11}{6}\)

\(=\dfrac{1}{4}-\dfrac{5}{4}+\dfrac{11}{6}\)

\(=-1+\dfrac{11}{6}\)

\(=\dfrac{5}{6}\)

Vậy ...

b) \(75\%:\dfrac{11}{5}-\left(0,5\right)^2.\left(-7\right)+2,5\left(\dfrac{23}{3}-\dfrac{17}{3}\right)\)

\(=\dfrac{3}{4}:\dfrac{11}{5}-\dfrac{1}{4}.\left(-7\right)+2,5.2\)

\(=\dfrac{15}{44} +\dfrac{7}{4}+5\)

\(=\dfrac{23}{11}+5\)

\(=\dfrac{78}{11}\)

Vậy ...

c) \(45:\dfrac{18}{7}+50\%-1,25\)

\(=45:\dfrac{18}{7}+\dfrac{1}{2}-\dfrac{5}{4}\)

\(=\dfrac{35}{2}+\dfrac{1}{2}-\dfrac{5}{4}\)

\(=18-\dfrac{5}{4}\)

\(=\dfrac{67}{4}\)

Vậy ...

e: =>2/7-x=2/5

=>7-x=5

=>x=2

f: =>2x+3/3=10/3

=>2x+3=10

=>2x=7

=>x=7/2

g: =>(14+x)/7=15/7

=>x+14=15

=>x=1

h: =>(2x+3)/x=13/x

=>2x+3=13

=>2x=10

=>x=5

4 tháng 7 2021

\(a,=3\sqrt{2}-12\sqrt{2}+8\sqrt{2}-5\sqrt{2}\)

\(=\sqrt{2}\left(3-12+8-5\right)=-6\sqrt{2}\)

\(b,=\left|\sqrt{2}-\sqrt{3}\right|+3\sqrt{2}=\sqrt{3}-\sqrt{2}+3\sqrt{2}=\sqrt{3}+2\sqrt{2}\)

\(c,=\sqrt{5}+\sqrt{5}+\dfrac{5}{\sqrt{5}}-1=3\sqrt{5}-1\)

\(d,=\sqrt{3-2.2\sqrt{3}+4}+\sqrt{\left(1+\sqrt{3}\right)^2}\)

\(=\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{\left(1+\sqrt{3}\right)^2}\)

\(=2-\sqrt{3}+1+\sqrt{3}=2\)

4 tháng 7 2021

a) \(3\sqrt{2}-4\sqrt{18}+2\sqrt{32}-\sqrt{50}=3\sqrt{2}-4\sqrt{9.2}+2\sqrt{16.2}-\sqrt{25.2}\)

\(=3\sqrt{2}-12\sqrt{2}+8\sqrt{2}-5\sqrt{2}=-6\sqrt{2}\)

b) \(\sqrt{\left(\sqrt{2}-\sqrt{3}\right)^2}+\sqrt{18}=\left|\sqrt{2}-\sqrt{3}\right|+\sqrt{9.2}=\sqrt{3}-\sqrt{2}+3\sqrt{2}\)

\(=2\sqrt{2}+\sqrt{3}\)

c) \(5\sqrt{\dfrac{1}{5}}+\dfrac{1}{3}\sqrt{45}+\dfrac{5-\sqrt{5}}{\sqrt{5}}=\sqrt{25.\dfrac{1}{5}}+\dfrac{1}{3}\sqrt{9.5}+\dfrac{\sqrt{5}\left(\sqrt{5}-1\right)}{\sqrt{5}}\)

\(=\sqrt{5}+\sqrt{5}+\sqrt{5}-1=3\sqrt{5}-1\)

d) \(\sqrt{7-4\sqrt{3}}+\sqrt{\left(1+\sqrt{3}\right)^2}=\sqrt{2^2-2.2.\sqrt{3}+\left(\sqrt{3}\right)^2}+\left|\sqrt{3}+1\right|\)

\(=\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{3}+1=\left|2-\sqrt{3}\right|+\sqrt{3}+1=2-\sqrt{3}+\sqrt{3}+1=3\)

23 tháng 8 2023

a) \(\dfrac{4}{7}< \dfrac{6}{7}\)

\(\dfrac{15}{23}>\dfrac{12}{23}\)

\(\dfrac{45}{60}=\dfrac{3}{4}\)

b) \(\dfrac{8}{9}>\dfrac{11}{18}\)

\(\dfrac{13}{18}>\dfrac{2}{3}\)

\(\dfrac{27}{25}>1\)

24 tháng 3 2017

1/Ta co :

\(\dfrac{15}{7}.\left(\dfrac{1}{5}-\dfrac{46}{45}\right)+\dfrac{46}{45}.\left(\dfrac{15}{7}-\dfrac{45}{46}\right)\)

=\(\dfrac{15}{7}.\dfrac{1}{5}-\dfrac{15}{7}.\dfrac{46}{45}+\dfrac{46}{45}.\dfrac{15}{7}-\dfrac{46}{45}.\dfrac{45}{46}\)

=\(\dfrac{15}{7}.\left(\dfrac{1}{5}-\dfrac{46}{45}+\dfrac{46}{45}\right)-1\)

=\(\dfrac{15}{7}.\dfrac{1}{5}-1\)

=\(\dfrac{3}{7}-1=\dfrac{-4}{7}\)

2/Ta co

\(\dfrac{43}{47}.\left(\dfrac{18}{37}+\dfrac{47}{43}\right)-\dfrac{18}{3}.\left(\dfrac{43}{47}+\dfrac{37}{36}\right)\)

=\(\dfrac{43}{47}.\dfrac{18}{37}+\dfrac{43}{47}.\dfrac{47}{43}-\dfrac{18}{37}.\dfrac{43}{47}+\dfrac{18}{37}.\dfrac{37}{36}\)

=\(\dfrac{18}{37}.\left(\dfrac{43}{37}-\dfrac{43}{37}+\dfrac{37}{36}\right)+1\)

=\(\dfrac{18}{37}.\dfrac{37}{36}+1\)

=\(\dfrac{1}{2}+1=\dfrac{3}{2}\)

tick cho mk nha

24 tháng 3 2017

t tick cho! ns nè,mai giải cho t vài bài vs...ko đùa!

a: \(\Leftrightarrow x^2=900\)

=>x=30 hoặc x=-30

b: \(\Leftrightarrow\dfrac{2}{3}:\left(-0.1x\right)=\dfrac{4}{3}:\dfrac{-2}{25}=-\dfrac{4}{3}\cdot\dfrac{25}{2}=-\dfrac{100}{6}=\dfrac{-50}{3}\)

=>0,1x=2/3:50/3=2/3x3/50=1/25

=>1/10x=1/25

hay x=1/25:1/10=10/25=2/5

d: \(\Leftrightarrow x^2=\dfrac{144}{25}\)

=>x=12/5 hoặc x=-12/5

20 tháng 10 2021

\(\dfrac{7}{23}\cdot\left[\dfrac{-8}{6}-\dfrac{15}{48}\right]\)

\(=\dfrac{7}{23}\cdot\dfrac{-64-15}{48}\)

\(=\dfrac{7}{23}\cdot\dfrac{-69}{48}\)

\(=-3\cdot\dfrac{7}{48}=\dfrac{-7}{16}\)

21 tháng 10 2021

viết sai đề bài r

 

5 tháng 5 2018

dài vậy?Ghi đáp án thôi nhé!hiha

6 tháng 5 2018

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