-5/12x2/11+-5/12x9/11+5/12
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\(\dfrac{-5}{12}\times\dfrac{2}{11}+\dfrac{-5}{11}\times\dfrac{9}{11}+\dfrac{5}{12}\\ =\dfrac{5}{12}\times\left(1-\dfrac{2}{11}\right)+\dfrac{-5}{11}\times\dfrac{9}{11}\\ =\dfrac{5}{12}\times\dfrac{9}{11}+\dfrac{-5}{11}\times\dfrac{9}{11}\\ =\dfrac{9}{11}\times\left(\dfrac{5}{12}-\dfrac{5}{11}\right)\\ =\dfrac{9}{11}\times\dfrac{-5}{132}=-\dfrac{15}{484}\)
\(\dfrac{5}{11}+\dfrac{4}{11}=\dfrac{9}{11}\\ \dfrac{11}{10}+\dfrac{9}{10}=\dfrac{20}{10}=2\\ \dfrac{11}{12}+\dfrac{5}{12}=\dfrac{16}{12}=\dfrac{4}{3}\\ \dfrac{7}{9}+\dfrac{5}{9}=\dfrac{12}{9}=\dfrac{4}{3}\)
\(\dfrac{5}{11}+\dfrac{4}{11}=1\)
\(\dfrac{11}{10}+\dfrac{9}{10}=\dfrac{20}{10}=2\)
\(\dfrac{11}{12}+\dfrac{5}{12}=\dfrac{16}{12}=\dfrac{4}{3}\)
\(\dfrac{7}{9}+\dfrac{5}{9}=\dfrac{12}{9}=\dfrac{4}{3}\)
\(\frac{5}{7}+\frac{5}{9}=\frac{45}{63}+\frac{35}{63}=\frac{80}{63}\)
\(\frac{11}{9}-\frac{11}{12}=\frac{44}{36}-\frac{33}{36}=\frac{11}{36}\)
1) 5|x-3| = \(\frac{5}{7}\)
=> |x-3| = \(\frac{1}{7}\)
\(\Rightarrow\orbr{\begin{cases}x-3=\frac{1}{7}\\x-3=\frac{-1}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{22}{7}\\x=\frac{20}{7}\end{cases}}\)
Vậy x \(\in\){\(\frac{22}{7};\frac{20}{7}\)}
2) |x-11/7| = 0
=> x-11/7 = 0
=> x = 11/7
- Cía chỗ bài tìm x thứ 2 mình viết nhầm số 11/12 thành 11/7
2) |x-11/12|=0
=> x-11/12 = 0
=> x = 11/12
\(\left(-\dfrac{1}{2}\right)^2\div\dfrac{1}{4}-2\times\left(-\dfrac{1}{2}\right)^2\\= \dfrac{1}{4}\div\dfrac{1}{4}-2\times\dfrac{1}{4}\\ =1-\dfrac{1}{2}\\ =\dfrac{1}{2}\)
\(\left(-2\right)^3\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right)\div\dfrac{5}{12}\)
= \(-6\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-\dfrac{11}{6}\right)\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{1}{2}\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{6}{5}\)
= \(\dfrac{1}{4}-\dfrac{6}{5}\)
= \(-\dfrac{19}{20}\)
\(\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\\ =\dfrac{58}{9}+\dfrac{7}{11}-\dfrac{40}{9}+\dfrac{26}{11}\\ =\dfrac{58}{9}-\dfrac{40}{9}+\dfrac{7}{11}+\dfrac{26}{11}\\ =12+3\\ =15\)
\(a,\left(\dfrac{-1}{2}\right)^2:\dfrac{1}{4}-2\left(-\dfrac{1}{2}\right)^2\)
\(=\left(-\dfrac{1}{2}\right)^2\left(4-2\right)\)
\(=\dfrac{1}{4}.2=\dfrac{1}{2}\)
\(b,\left(-2\right)^3.\dfrac{-1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right):\dfrac{5}{12}\)
\(=\left(-8\right).\dfrac{-1}{24}+\left(-\dfrac{1}{2}\right).\dfrac{12}{5}\)
\(=\dfrac{1}{3}+\left(-\dfrac{1}{5}\right)=\dfrac{2}{15}\)
\(c,\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\)
\(=\dfrac{701}{99}-\dfrac{206}{99}=\dfrac{495}{99}=5\)
\(d,10\dfrac{1}{5}-5\dfrac{1}{2}.\dfrac{60}{11}+\dfrac{3}{15\%}\)
\(=\dfrac{51}{5}-30+20=\dfrac{1}{5}\)
\(e,\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)
\(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}.\left(-\dfrac{7}{11}\right)\)
\(=-\dfrac{5}{11}\)
\(f,\dfrac{-5}{7}.\dfrac{2}{11}+\left(-\dfrac{5}{7}\right).\dfrac{9}{11}+1\dfrac{5}{7}\)
\(=\left(-\dfrac{5}{7}\right)\left(\dfrac{2}{11}+\dfrac{9}{11}\right)+\dfrac{12}{7}\)
\(=\left(-\dfrac{5}{7}\right)+\dfrac{12}{7}=1\)
\(\dfrac{5}{2}-\dfrac{11}{12}+\dfrac{9}{14}\)
\(=\dfrac{5\cdot42}{2\cdot42}-\dfrac{11\cdot7}{12\cdot7}+\dfrac{9\cdot6}{14\cdot6}\)
\(=\dfrac{210}{84}-\dfrac{77}{84}+\dfrac{54}{84}\)
\(=\dfrac{210-77+54}{84}\)
\(=\dfrac{187}{84}\)
\(\dfrac{5}{2}-\dfrac{11}{12}+\dfrac{9}{14}\text{=}\dfrac{210}{84}-\dfrac{77}{84}+\dfrac{54}{84}\text{=}\dfrac{210-77+54}{84}\text{=}\dfrac{187}{84}\)
a, -5/11.7/15.(11/-5)(-30)
=(-5/11.11/-5).(7/15.-30)
=1.7.(-30)/15
=1.7.(-2).15/15
=1.7.(-2)
=-14
b,(11/12):(33/36).3/5
=11/12:(11.3/12.3).3/5
=11/12:11/12.3/5
=1.3/5
=3/5
c,(-5/-9).3/11+(-13/18).3/11
=5/9.3/11+ -13/18.3/11
=3/11.(5/9+ -13/18)
=3/11.(10/18+ -13/18)
=3/11.-3/18
= -9/198
= -1/22
Bài 2:
a,-7/15.5/8.15/7.(-16)
=(-7/15.15/7)(5/8. -16)
= -1.-10
= 10
b,(-1/-2).16/5+(-1/-2)(-11/5)
= 1/2.16/5+1/2. (-11/5)
=1/2.(16/5+ -11/5)
=1/2.5/5
=1/2.1
=1/2
học tốt nha bạn. chúc bạn thành công
A = \(\dfrac{-5}{12}\)x\(\dfrac{2}{11}\)+\(\dfrac{-5}{12}\)x\(\dfrac{9}{11}\)+\(\dfrac{5}{12}\)
A= \(\dfrac{-5}{12}\)(\(\dfrac{2}{11}\)+\(\dfrac{9}{11}\)-1)
A = 0