cmr a>b>0 thi cana - can b < cana-b
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30 tháng 1 2022
Xét ΔBAM và ΔCAN , có :
AB = AC ( gt )
A1 = A2 ( gt )
Đường thẳng d chung ( M , N thuộc d )
=> ΔBAM = ΔCAN (đpcm)
KN
0
DT
Đỗ Thanh Hải
CTVVIP
31 tháng 3 2021
Canadian Culture
July 1st is Canada Day. Canada Day is the (1) ……………… of the formation of the provinces into Canada, which was created in 1867. Canada became an (2) ……………… territory of England back on July 1st, 1867. Canada Day is also a Statutory Holiday. Canadians across the country celebrate in many (3) ………………The Government of Canada sponsors fireworks displays and celebrations at city halls across the country. In Ottawa, at the Parliament Buildings there is a noon show with the Prime Minister and the Governor General in attendance to (4) ………………performances of Canadian musicians and singers. Events continue throughout the day.
Many families go to parks and beaches and enjoy picnics and local events such as musical concerts, parades and fireworks. Many Canadians proudly (5) ………………the Canadian flag at parades to celebrate the birthday of the country. At many events, the National Anthem ‘O Canada’ is played and sung by everyone in attendance. For all Canadians, Canada Day marks the beginning of summer.
11 |
Choose the best answer.
1
1. A. ceremony B. party C. celebration D. occasion
2. A. dependent B. independent C. dependable D. undependable
3. A. methods B. roads C. paths D. ways
4. A. see B. watch C. look at D. witness
5. A. wave B. plug C. hold D. keep
| 2 |
Decide if the statements are true (T) or false (F).
1. The celebration falls on the very beginning of June. ........T.....
2. England used to be the colony of Canada. .....F........
3. Some very important persons attend the celebration in Ottawa.....T.....
4. It is not an event for family activities. ......F.......
5. Canada Day is celebrated when a new season has come. T
24 tháng 3 2021
a) Ta có: \(AN=NB=\dfrac{AB}{2}\)(N là trung điểm của AB)
\(AM=MC=\dfrac{AC}{2}\)(M là trung điểm của AC)
mà AB=AC(ΔABC cân tại A)
nên AN=NB=AM=MC
Xét ΔANC và ΔAMB có
AN=AM(cmt)
\(\widehat{NAC}\) chung
AC=AB(ΔABC cân tại A)
Do đó: ΔANC=ΔAMB(c-g-c)
b) Ta có: ΔANC=ΔAMB(cmt)
nên NC=MB(Hai cạnh tương ứng) và \(\widehat{ABM}=\widehat{ACN}\)(hai góc tương ứng)
LN
0
VT
1
a>b>0 => a-b>0=> (√a)^2-(√b)^2>0
=> (√a-√b).(√a+√b)>0
mà √a + √b >0
=> bạn ngu