tìm chữ số a và c biết
ac.ac=acc
dấu chấm là dấu nhân nha .Các bạn giúp minh nhé
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=> 3A = 3 [ 1.2 + 2.3 + 3.4 + ... + (n-1).n ]
=> 3A = 1.2.3 + 2.3.3 + 3.4.3 +... + 1001.1002.3
=> 3A = 1.2.3 + 2.3 . ( 4-1 ) +3.4.( 5-2 ) + ... + 1001.1002 ( 1003-1000 )
=> 3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 +... + 1001.1002 .1003 - 1000.1001.1002
=> 3A = 1001.1002.1003
=> A = 1001 . 1002 . 1003 : 3
=> A = ?
131 . x - 942 = 2^7 . 2^3
131 . x - 942 = 2^10
131 . x - 942 = 1024
131 . x = 1024 + 942
131 . x = 1966
x = 1966 : 131
x \(\approx15\)
b ) [ ( x + 32 ) - 17 ] . 2 = 42
[ ( x + 32 ) - 17 ] = 42 : 2
( x + 32 ) - 17 = 21
x + 32 = 21 + 17
x + 32 = 38
x = 38 - 32
x = 6
a, \(\dfrac{4}{7}\). \(\dfrac{a}{b}\) - \(\dfrac{1}{3}\) = \(\dfrac{1}{21}\)
\(\dfrac{4}{7}\).\(\dfrac{a}{b}\) = \(\dfrac{1}{21}\) + \(\dfrac{1}{3}\)
\(\dfrac{4}{7}\).\(\dfrac{a}{b}\) = \(\dfrac{8}{21}\)
\(\dfrac{a}{b}\) = \(\dfrac{8}{21}\):\(\dfrac{4}{7}\)
\(\dfrac{a}{b}\) = \(\dfrac{2}{3}\)
b, \(\dfrac{a}{b}\) + \(\dfrac{2}{3}\).\(\dfrac{1}{3}\) = \(\dfrac{2}{3}\)
\(\dfrac{a}{b}\) + \(\dfrac{2}{9}\) = \(\dfrac{2}{3}\)
\(\dfrac{a}{b}\) = \(\dfrac{2}{3}\) - \(\dfrac{2}{9}\)
\(\dfrac{a}{b}\) = \(\dfrac{4}{9}\)
c, \(\dfrac{a}{b}\) - \(\dfrac{1}{2}.\)\(\dfrac{2}{3}\) = \(\dfrac{2}{7}\)
\(\dfrac{a}{b}\) - \(\dfrac{1}{3}\) = \(\dfrac{2}{7}\)
\(\dfrac{a}{b}\) = \(\dfrac{2}{7}\) + \(\dfrac{1}{3}\)
\(\dfrac{a}{b}\) = \(\dfrac{13}{21}\)
d, \(\dfrac{11}{13}\): \(\dfrac{a}{b}\): \(\dfrac{2}{3}\) = 2\(\dfrac{7}{13}\)
\(\dfrac{11}{13}\): \(\dfrac{a}{b}\):\(\dfrac{2}{3}\) = \(\dfrac{33}{13}\)
\(\dfrac{11}{13}\): \(\dfrac{a}{b}\) = \(\dfrac{33}{13}\) \(\times\) \(\dfrac{2}{3}\)
\(\dfrac{11}{13}\): \(\dfrac{a}{b}\) = \(\dfrac{66}{39}\)
\(\dfrac{a}{b}\) = \(\dfrac{11}{13}\) : \(\dfrac{66}{39}\)
\(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)
a)\(2.18.6+3.19.4+12.63\)
\(=2.6.18+3.4.19+12.63\)
\(=12.18+12.19+12.63\)
\(=12.\left(18+19+63\right)\)
\(=12.100\)
\(=1200\)
b)\(12.19+12.34+12.20+88.27\)
\(=12.19+12.34+12.20+22.4.3.9\)
\(=12.19+12.34+12.20+4.3.22.9\)
\(=12.19+12.34+12.20+12.198\)
\(=12.\left(19+34+20+198\right)\)
\(=12.271\)
\(=3252\)
c) \(28.17+66.14\)
\(=14.2.17+66.14\)
\(=14.34+66.14\)
\(=14.\left(34+66\right)\)
\(=14.100\)
\(=1400\)
a,2.18.6=216; 3.19.4=228;12.63= 756;216+228+756=1200 b,12.19=228;12.34=408;12.20=240;88.27=2376;228+408+240+2376=3252 c,1/1
8.19 = 8.(20-1) = 8.20-8 = 160-8 = 152
65.98 = 65.(100-2) = 65.100-65.2 = 6500-130 = 6370
a=1
c=10 vì ac.ac=acc mà 10.10=100
bạn có thể ghi cách làm ro ràng ra duoc ko