mn cho mik biết 32 x 3/4 [giải chi tiết ]
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a ) x - 5 \(\in\)B ( 6 )
\(\Rightarrow\)x - 5 \(\in\){ 0 ; 6 ; 12 ; 18 ; 24 ; 30 ; 36 ; 42 ; 48 ; ..... }
\(\Rightarrow\)x \(\in\){ 5 ; 11 ; 17 ; 23 ; 29 ; 35 ; 41 ; 47 ; 53 ; .... }
b ) x - 1 \(⋮\)4
\(\Rightarrow\)x - 1 \(\in\)B ( 4 )
\(\Rightarrow\)x - 1 \(\in\){ 0 ; 4 ; 8 ; 12 ; 16 ; 20 ; 24 ; 28 ; 32 ; 36 ; 40 ; ..... }
\(\Rightarrow\)x \(\in\){ 1 ; 5 ; 9 ; 13 ; 17 ; 21 ; 25 ; 29 ; 33 ; 37 ; 41 ; .... }
a, 10 + 2x = 45 ÷ 43
10 + 2x = 45/43
2x = 45/43 - 10
2x = -385/43
x = -385/43 ÷ 2
x = -385/86
b, 2x - 138 = 23.32
2x - 138 = 736
2x = 736 + 138
2x = 874
x = 874 ÷ 2
x = 437
c, 231 - ( x - 6 ) = 1339 ÷ 13
231 - ( x - 6 ) = 103
x - 6 = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
d, x + 5.2 - ( 32 + 16.3 ÷ 6 - 15 ) = 0
x + 10 - 25 = 0
x + 10 = 0 + 25
x + 10 = 25
x = 25 - 10
x = 15
a) 10 + 2 . x = 45 : 43
2 . x = 45/43 -10
2 . x = -385/43
x = -385/43 : 2
x = -385/86
b) 2 . x - 138 = 23 . 32
2 . x - 138 = 736
2 . x = 736+138
2 . x = 874
x = 874 : 2
x = 437
c) 231 - (x -6) = 1339 : 13
231 - (x -6) = 103
x - 6 = 231 -103
x - 6 = 98
x = 98 +6
x = 104
d) x + 5 . 2 - (32 +16 . 3 : 6 - 15) = 0
x + 5 . 2 - (32 + 48 : 6 - 15) = 0
x + 5 . 2 - (32 + 8 - 15) = 0
x + 5 . 2 - 25 = 0
x + 10 - 25 = 0
x + 10 = 0 + 25
x + 10 = 25
x = 25 - 10
x = 15
13/32 + 3/21 + 1/4 + 19/32 + 18/21 + 45/60
= ( 13/32 + 19/32 ) + ( 3/21 + 18/21 ) + ( 1/4+ 45/60 )
= 32/32 + 21/21 + (1/4+3/4)
= 1+1+4/4
=1+1+1
=3
Chúc bạn học tốt :333
\(2^2.\left(x-3\right)=2^6\\ \Rightarrow x-3=16\\ \Rightarrow x=19\)
`@` `\text {Ans}`
`\downarrow`
`j)`
\(x^{17}\div x^{12}=x^{17-12}=x^5\)
`k)`
\(x^8\div x^5=x^{8-5}=x^3\)
`r)`
\(a^5\div a^5=a^{5-5}=a^0=1\)
`l)`
\(x^4\div x=x^{4-1}=x^3\)
`m)`
\(x^7\div x^6=x^{7-6}=x\)
`n)`
\(x^9\div x^9=x^{9-9}=x^0=1\)
`o)`
\(a^{12}\div a^5=a^{12-5}=a^7\)
`p)`
\(a^8\div a^6=a^{8-6}=a^2\)
`q)`
\(a^{10}\div a^7=a^{10-7}=a^3\)
`r(2),`
\(1024\div4=2^{10}\div2^2=2^8\)
`t)`
\(512\div2^3=2^9\div2^3=2^6\)
\(1,2\sqrt{27}+5\sqrt{12}-3\sqrt{48}\\ =2.3\sqrt{3}+5.2\sqrt{3}-3.4\sqrt{3}\\ =6\sqrt{3}+10\sqrt{3}-12\sqrt{3}\\ =4\sqrt{3}\)
\(2,\sqrt{147}+\sqrt{75}-4\sqrt{27}\\ =7\sqrt{3}+5\sqrt{3}-4.3\sqrt{3}\\ =7\sqrt{3}+5\sqrt{3}-12\sqrt{3}\\ =\sqrt{3}\left(7+5-12\right)\\ =0\)
\(3,3\sqrt{2}\left(4-\sqrt{2}\right)+3\left(1-2\sqrt{2}\right)^2\\ =3\sqrt{2}.\left(4-\sqrt{2}\right)+3\left(1-4\sqrt{2}+8\right)\\ =12\sqrt{2}-6+3-12\sqrt{2}+24\\ =21\)
\(4,2\sqrt{5}-\sqrt{125}-\sqrt{80}+\sqrt{605}\\ =2\sqrt{5}-5\sqrt{5}-4\sqrt{5}+11\sqrt{5}\\ =\sqrt{5}\left(2-5-4+11\right)\\ =4\sqrt{5}\)
1: =6căn 3+10căn 3-12căn 3=4căn 3
2: =7căn 3+5căn 3-12căn 3=0
3: =12căn 2-6+3(9-4căn 2)
=12căn 2-6+27-12căn 2=21
4: =2căn 5-5căn 5+4căn 5+9 căn 5
=10căn 5
1. Tìm x
a) 1+2+3+...+x = 210
=> \(\frac{x\left(x+1\right)}{2}=210\)
=> x = 20
b) \(32.3^x=9.3^{10}+5.27^3\)
=>\(32.3^x=9.3^{10}+5.3^9\)(\(27^3=\left(3^3\right)^3=3^9\))
=>\(32.3^x=9.3.3^9+5.3^9\)
=>\(32.3^x=3^9\left(9.3+5\right)\)
=>\(32.3^x=3^9.32\)
=>x = 9
2.
Ta có 2A = 3A - A
=> 2A = \(3\left(1+3+3^2+3^3+....+3^{10}\right)\)\(-\)\(1-3-3^2-3^3-....-3^{10}\)
=> 2A = \(3+3^2+3^3+.....+3^{11}-\)\(1-3-3^2-3^3-...-3^{10}\)
=> 2A = \(3^{11}-1\)
=> 2A+1 = \(3^{11}-1+1\)=\(3^{11}\)
=> n = 11
Ta có : a)1 + 2 + 3 + ... + x = 210
=> \(\frac{x\left(x+1\right)}{2}=210\)
=> x(x + 1) = 420
=> x(x + 1) = 20.21
=> x = 20
4 cách điều chế NaOH :
Pt : \(2Na+2H_2O\rightarrow2NaOH+H_2\)
\(Na_2O+H_2O\rightarrow2NaOH\)
\(2NaCl+H_2O\xrightarrow[có.màng.ngăn]{điện.phân}2NaOH+H_2+Cl_2\)
\(Ba\left(OH\right)_2+Na_2SO_4\rightarrow BaSO_4+2NaOH\)
Chúc bạn học tốt
32/1 x 3/4= 96/ 4= 24
\(32\times\dfrac{3}{4}=\dfrac{96}{4}=24\)