\(\frac{2^2}{1.3}\).\(\frac{3^2}{2.4}\). \(\frac{4^2}{3.5}\). \(\frac{5^2}{4.6}\)giải hộ mình nhóe
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\(A=\frac{2^2}{1.3}\cdot\frac{2^2}{2.4}\cdot\frac{2^2}{3.5}\cdot\frac{2^2}{4.6}\)
\(A=\frac{4}{3}\cdot\frac{1}{2}\cdot\frac{4}{15}\cdot\frac{1}{6}\)
\(A=\frac{4.1.4.1}{3.2.15.6}\)
\(A=\frac{4}{135}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.\frac{5^2}{4.6}\)
\(=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}.\frac{5.5}{4.6}\)
\(=\frac{2.3.4.5}{1.2.3.4}.\frac{2.3.4.5}{3.4.5.6}\)
\(=\frac{5}{1}.\frac{2}{6}\)
\(=\frac{5}{1}.\frac{1}{3}\)
\(=\frac{5}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= \(\frac{2.2}{1.3}+\frac{3.3}{2.4}+\frac{4.4}{3.5}+\frac{5.5}{4.6}+\frac{6.6}{5.7}\)
= \(\frac{2.3.4.5.6}{1.2.3.4.5}+\frac{2.3.4.5.6}{3.4.5.6.7}\)
= \(\frac{2}{1}+\frac{6}{7}\)
= 2\(\frac{6}{7}\)
Mình nghĩ zậy !!!!!!!!!!!!!!!!!!
![](https://rs.olm.vn/images/avt/0.png?1311)
C=2.2.3.3.4.4.5.5/1.3.2.4.3.5.4.6
C=(2.3.4.5).(2.3.4.5)/(1.2.3.4).(3.4.5.6)
C=2.5/6
C=5/3
C=2^2/1.3.3^2/2.4.5^2/3.5.4^2/4.6
C= 2.2.3.3.5.5.4.4/1.3.2.4.3.5.4.6
C=(2.3.4.5).(2.3.4.5)/(1.2.3.4).(3.4.5.6)
C=5.2/6
C=5/3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.,,\frac{50^2}{49.51}\)
=\(\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}.,,\frac{50.50}{49.51}\)
=\(\frac{\left(2.3.4...50\right).\left(2.3.4...50\right)}{\left(1.2.3....49\right).\left(3.4.5....51\right)}\)
=\(\frac{50.2}{1.51}\)
=\(\frac{100}{51}\)
\(=\frac{2.3.4...50}{1.2.3...49}.\frac{2.3.4...50}{3.4.5...51}=50.\frac{2}{51}=\frac{100}{51}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Yêu cầu các CTV, các bạn làm sai giúp nhé! Nếu bạn muốn đáp án tham khảo thì sau đề vòng 1 mk sẽ giải nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
=4/3.9/8.16/15.25/4096(CÁI NÀY MÌNH BIẾN NÓ VỀ PHÂN SỐ NHA)
=5/512 (BẠN THỰC HIỆN PHÉP TÍNH TỪ TRÁI SANG PHẢI NHÉ)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^2}{1.3}+\frac{3^2}{2.4}+...+\frac{100^2}{99.101}\\ =\frac{2.2}{1.3}+\frac{3.3}{2.4}+...+\frac{100.100}{99.101}\\ =\frac{2.}{1.}\frac{3.}{2.}\frac{...}{...}\frac{100}{99}+\frac{2.}{3.}\frac{3.}{4.}\frac{...}{...}\frac{100}{101}\\ =\frac{100}{1}+\frac{2}{101}\\ =\frac{10100}{101}+\frac{2}{101}\\ =\frac{10102}{101}\)
\(\frac{2^2}{1.3}+\frac{3^2}{2.4}+\frac{4^2}{3.5}+...+\frac{100^2}{99.101}\)
\(=\frac{2.2}{1.3}+\frac{3.3}{2.4}+\frac{4.4}{3.5}+...+\frac{100.100}{99.101}\)
\(=\frac{2.3.4...100}{1.2.3...99}.\frac{2.3.4...100}{3.4.5...101}\)
\(=100.\frac{2}{101}\)
\(=\frac{200}{101}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.\frac{5^2}{4.6}\)
\(\Leftrightarrow\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}.\frac{5.5}{4.6}\)
\(\Leftrightarrow\frac{2.2.3.3.4.4.5.5}{1.3.2.4.3.5.4.6}\)
\(\Leftrightarrow\frac{2.5}{1.6}\)
\(\Leftrightarrow\frac{10}{6}=\frac{5}{3}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.\frac{5^2}{4.6}=\frac{2.2.3.3.4.4.5.5}{1.2.3.3.4.4.5.6}\)
\(=\frac{2.5}{1.2.3}=\frac{5}{3}.\)