8/9x15/16x24/25x35/36x48/49x63/64x80/81x99/100
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DD
0
TA
25 tháng 5 2021
`3/4 xx 8/9 xx 15/16 xx 24/25 xx 35/36`
`= (3xx8xx15xx24xx35)/(4xx9xx16xx25xx36)`
`=(3xx4xx2xx5xx3xx4xx6xx7xx5)/(4xx3xx3xx4xx4xx5xx5xx6xx6)`
`=(2xx7)/(4xx6)`
`=(2xx7)/(2xx2xx6)`
`=7/12`
J
25 tháng 5 2021
\(\dfrac{3}{4}\times\dfrac{8}{9}\times\dfrac{15}{16}\times\dfrac{24}{25}\times\dfrac{35}{36}\)
= \(\dfrac{3\times8\times15\times24\times35}{4\times9\times16\times25\times36}\)
= \(\dfrac{3\times\left(2\times4\text{}\text{}\right)\times\left(3\times5\right)\times\left(6\times4\right)\times\left(5\times7\right)}{4\times\left(3\times3\right)\times\left(4\times4\right)\times\left(5\times5\right)\times\left(6\times6\right)}\)
=\(\dfrac{2\text{}\text{}\times3\times6\times\left(5\times7\right)}{3\times4\times5\times\left(6\times6\right)}\)
=\(\dfrac{\text{}\text{}7}{2\times6}\)= \(\dfrac{7}{12}\)
TL
2
1 tháng 5 2016
\(\frac{1\cdot3}{2\cdot2}\cdot\frac{2\cdot4}{3\cdot3}\cdot\frac{3\cdot5}{4\cdot4}\cdot...\cdot\frac{99\cdot101}{100\cdot100}\)
\(\frac{1\cdot101}{2\cdot100}\)
\(\frac{101}{200}\)
NM
1
AH
Akai Haruma
Giáo viên
27 tháng 9 2023
Lời giải:
\(\frac{3}{4}\times \frac{8}{9}\times \frac{15}{16}\times ....\times \frac{99}{100}\)
\(=\frac{3\times 8\times 15\times ....\times 99}{4\times 9\times 16\times ....\times 100}\)
\(=\frac{(1\times 3)\times (2\times 4)\times (3\times 5)\times ...\times (9\times 11)}{2\times 2\times 3\times 3\times 4\times 4\times ....\times 10\times 10}\)
\(=\frac{(1\times 2\times 3\times ...\times 9)\times (3\times 4\times 5\times ....\times 11)}{(2\times 3\times 4\times....\times 10)\times (2\times 3\times 4\times ...\times 10)}\)
\(=\frac{1\times 2\times 3\times ....\times 9}{2\times 3\times 4\times ....\times 10}\times \frac{3\times 4\times 5\times ...\times 11}{2\times 3\times 4\times ...\times 10}\)
\(=\frac{1}{10}\times \frac{11}{2}=\frac{11}{20}\)
3 tháng 8 2023
\(\dfrac{8}{9}x\dfrac{15}{16}x\dfrac{24}{25}x...\dfrac{8099}{8100}\)
\(=\dfrac{2x4}{3x3}x\dfrac{3x5}{4x4}x\dfrac{4x6}{5x5}x...x\dfrac{89x91}{90x90}\)
\(=\dfrac{2x4x3x5x4x6x...x89x91}{3x3x4x4x5x5x...x90x90}\)
\(=\dfrac{2x91}{3x90}=\dfrac{91}{135}\)