Tính : E=49^3.7^4/345^5
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a) \(=\frac{3}{17}-\frac{2}{345}+\frac{5}{12}+\frac{2}{345}-\frac{3}{17}+\frac{1}{12}\)
\(=\left(\frac{3}{17}-\frac{3}{17}\right)+\left(\frac{2}{345}-\frac{2}{345}\right)+\left(\frac{5}{12}+\frac{1}{12}\right)\)
\(=\frac{6}{12}=\frac{1}{2}\)
b) \(=-\frac{49}{25}-\frac{5}{36}+\frac{4}{123}+\frac{49}{25}-\frac{4}{123}-\frac{1}{36}\)
\(=\left(-\frac{49}{25}+\frac{49}{25}\right)+\left(\frac{4}{123}-\frac{4}{123}\right)-\left(\frac{5}{36}+\frac{1}{36}\right)\)
\(=-\frac{6}{36}=-\frac{1}{6}\)
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a) ( - 5) . (- 345) = 1725
b) 49.|-76| = 49 . 76 = 3724
c) |-26|.|-32| = 26 . 32 = 832
d) − 15 2 = ( - 15 ) . ( - 15 ) = 225
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Viết vậy đúng đó em
A = 5/(3.7) + 5/(7.11) + 5/(11.15) + ... + 5/(2019.2023)
= 5/4 . [4/(3.7) + 4/(7.11) + 4/(11.15) + ... + 4/(2019.2023)]
= 5/4 . (1/3 - 1/7 + 1/7 - 1/11 + 1/11 - 1/15 + ... + 1/2019 - 1/2023)
= 5/4 . (1/3 - 1/2023)
= 5/4 . 2020/6069
= 2525/6069
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 2 x 4 x 8 x 0,5 x 0,125 x 0,25 x ( 0,4321 + 0,5679 )
= ( 2 x 0,5 ) x ( 4 x 0,25 ) x ( 0,125 x 8 ) x ( 0,4321 + 0,5679 )
= 1 x 1 x 1 x ( 0,4321 + 0,5679 )
= 1 x ( 0,4321 + 0,5679 )
= 1 x 1 = 1
b, 3,7 x 3,8 + 8,3 x 3,7 - 0,4 x 3,7 x 5
= 3,7 x ( 3,8 + 8,3 ) - ( 0,4 x 5 ) x 3,7
= 3,7 x 12,1 - 2 x 3,7
= 3,7 x ( 12,1 - 2 )
= 3,7 x 10,1 = 37,37
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)