tìm x biết:12/5÷x=14/3×4/7
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\(2\left(x-3\right)-5\left(x-4\right)=-7+14.\left(-3\right)\)
\(2x-6-5x+20=-7+\left(-42\right)\)
\(\left(2x-5x\right)+\left(-6+20\right)=-49\)
\(-3x+14=-49\)
\(-3x=-63\)
\(x=21\)
14-(7-x+3)=5-[4-(5-3)] 14-(7-x+3)=5-[4-2] 14-(7-x+3)=5-2 14-(7-x+3)=3 7-x+3=14-3 7-x+3=11 7-x=11-3 7-x=8 x=7-8 x=-1 vậy x=-1
14-(7-x+3)=5-[4-(5-3] 14-(7-x+3)=5-[4-2] 14-(7-x+3)=5-2 14-(7-x+3)=3 7-x +3=14-3 7-x+3=11 7-x=11-3 7-x=8 x=7-8 x=-1
a, 12 - (2\(x^2\) - 3) = 7
2\(x^2\) - 3 = 12 - 7
2\(x^2\) - 3 = 5
2\(x^2\) = 8
\(x^2\) = 4
\(\left[{}\begin{matrix}x=-2\\x=2\end{matrix}\right.\)
a, 11/12 - ( 2/5 + x ) = 2/3
<=> \(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}=\frac{1}{4}\)
=> x=\(\frac{1}{4}-\frac{11}{12}=-\frac{2}{3}\)
b, 2x . ( x - 1/7 ) = 0
<=>\(\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)<=> \(\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)
vậy x={\(0;\frac{1}{7}\)}
c, 3/4 + 1/4 : x = 2/5
<=>\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)
<=> \(x=\frac{1}{4}:\left(-\frac{7}{20}\right)=-\frac{5}{7}\)
vậy x=-5/7
a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
\(\Leftrightarrow\frac{11}{12}-\frac{2}{5}-x=\frac{2}{3}\)
\(\Leftrightarrow-x=\frac{2}{3}-\frac{11}{12}+\frac{2}{5}=\frac{3}{20}\)
\(\Leftrightarrow x=-\frac{3}{20}\)
b) \(2x\left(x-\frac{1}{7}\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)
c) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
\(\Leftrightarrow\frac{1}{4x}=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)
\(\Leftrightarrow4x=\frac{-20}{7}\)
\(\Leftrightarrow x=-\frac{5}{7}\)
b1
A,=\(\frac{35}{54}\) B,=4
b2
A,x=\(\frac{7}{15}\) B=\(\frac{-9}{7}\)
CHÚC BẠN HỌC GIỎI
12/5:X=14/3x4/7
12/5:X=8/3
X=12/5:8/3
X=9/10