\(\frac{8}{19}\) * \(\frac{5}{11}\) + \(\frac{8}{19}\) * \(\frac{6}{11}\) + \(\frac{11}{19}\)
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D = 8/19 . 5/11 + 7/11 . 8/19 - 8/19 . 1/11
= 8/19 . ( 5/11 + 7/11 - 1/11)
= 8/19 . 5 + 7 - 1 / 11
= 8/19 . 11/11
= 8/19 . 1
= 8/19
#Hoq chắc _ Baccanngon
=\(\frac{7}{19}.\)\(\left(\frac{8}{11}+\frac{2}{11}-\frac{5}{11}\right)\)
=\(\frac{7}{19}.\frac{5}{11}\)
=\(\frac{35}{209}\)Tk mk nhen bn yêu , kb nx ak
- 3 phân số \(\frac{7}{19}\)lận mà bạn ? Đâu phải hai số đâu mà gộp lại -.-
\(1\)) \(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)
\(=\frac{7}{19}\left(\frac{8}{11}+\frac{3}{11}\right)+\frac{12}{19}\)
\(=\frac{7}{19}+\frac{12}{19}\)
\(=1\)
\(2\)) \(\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{9}-\frac{4}{11}}\)
\(=\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{2\left(\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}\right)}\)
\(=\frac{1}{2}\)
1. \(\frac{7}{19}\times\frac{8}{11}+\frac{7}{19}\times\frac{3}{11}+\frac{12}{19}\)
\(=\frac{7}{19}\left(\frac{8}{11}+\frac{3}{11}\right)+\frac{12}{19}\)
\(=\frac{7}{19}\times1+\frac{12}{19}=\frac{19}{19}=1\)
2. \(\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{9}-\frac{4}{11}}\)
\(=\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{2\left(\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}\right)}=\frac{1}{2}\)
\(\frac{-5}{18}+\frac{5}{9}-\frac{11}{36}\)
\(=\frac{-10}{36}+\frac{20}{36}-\frac{11}{36}\)
\(=-\frac{1}{36}\)
vậy_
\(\frac{-5}{18}+\frac{5}{9}-\frac{11}{36}\)
\(=\frac{5}{18}-\frac{11}{36}\)
\(=\frac{-1}{36}\)
___________________________
\(\frac{-39}{44}:1\frac{2}{11}\)
\(=\frac{-39}{44}:\frac{13}{11}\)
\(=\frac{-3}{4}\)
_________________________
\(\frac{-7}{11}.\frac{11}{19}+\frac{-7}{11}.\frac{8}{19}+\frac{-4}{11}\)
\(=\frac{-7}{11}.\left(\frac{11}{19}+\frac{8}{19}\right)+\frac{-4}{11}\)
\(=\frac{-7}{11}.1+\frac{-4}{11}\)
\(=\frac{-7}{11}+\frac{-4}{11}\)
\(=\frac{-11}{11}=-1\)
=8/19x(5/11+7/11)+8/11x1/19
=8/19x1+8/11x1/19
=8x1/19+8/11x1/19
=1/19x(8+8/11)
còn lại bấm máy tính
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
E = 7/19 . 8/11 + 7/19 . 3/11 +12/19
= 7/19 . ( 8/11 + 3/11 ) + 12/19
= 7/19 . 11/11 + 12/19
= 7/19 . 1 + 12/19
= 7/19 + 12/19
= 7 + 12 / 19
= 19/19
= 1
\(A=\frac{7}{19}.\frac{8}{11}.\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\left(\frac{7}{19}\right)^2.\frac{8}{11}.\frac{11}{3}+\frac{12}{19}\)
\(\Rightarrow A=\left(\frac{7}{19}\right)^2.\frac{8}{3}+\frac{12}{19}\)
\(\Rightarrow A=\frac{392}{1083}+\frac{12}{19}\)
\(\Rightarrow A=\frac{1076}{1083}\)
\(A=\frac{56}{209}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{3971}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{1083}+\frac{12}{19}\)
\(A=\frac{1076}{1083}\)
8/19 × 5/11 + 8/19 × 6/11 + 11/19
= 8/19 × (5/11 + 6/11) + 11/19
= 8/19 × 1 + 11/19
= 8/19 + 11/19
= 1
Ủng hộ mk nha ♡_♡