Question

[Han Luu Ngoc]

giai phuong trinh

a)\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=3x\left(1-\frac{x-1}{x+1}\right)\)

b)\(x^4+5x^3+12x^2+5x+13=0\)

c)\(\frac{3x-1}{x-1}-\frac{2x+5}{x+3}+\frac{4}{x^2+2x-3}=1\)

Answer 1

[Thắng Nguyễn]

a)\(\Leftrightarrow-\frac{x}{x+1}+\frac{1}{x+1}+\frac{x}{x-1}+\frac{1}{x-1}=-\frac{3x^2}{x+1}+\frac{3x}{x+1}+3x\)

\(\Rightarrow\frac{3x^2}{x+1}-\frac{4x}{x+1}+\frac{1}{x+1}+\frac{x}{x-1}-3x+\frac{1}{x-1}=0\)

\(\Leftrightarrow-\frac{2x\left(3x-5\right)}{\left(x-1\right)\left(x+1\right)}=0\)

\(\Rightarrow\int^{\frac{x-1}{1}=0}_{\frac{x+1}{1}=0}\Rightarrow x=0\)

=>3x=5

\(\Rightarrow x=\frac{3}{5}\)

vậy \(x=\frac{3}{5}\) hoặc 0 

b)x = -(20309916*i+23555105)/9277755;

x = -(985155752*i-35635815)/916564140;

x = (985155752*i+35635815)/916564140;

x = (20309916*i-23555105)/9277755;

c)\(\Leftrightarrow\frac{x+2}{x-1}=\frac{1}{1}\Rightarrow\left(x+2\right)1=\left(x-1\right)1\)

vì \(\left(x+2\right)1\ne\left(x-1\right)1\)

=>x vô nghiệm hoặc đề sai

Answer 2

[haibara]

x=1+2+3=6 hê