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1 phần 2 nhân 3 phần 4 cộng 1 phần 2 nhân 1 phần 4 ; 11 phần 3 nhân 26 phần 7 trừ 20 phần 7 nhân 8 phần 30
A=5^10 .9+5^10.7 / 5^9.2^4
A=5^10.(9+7) / 5^9.16
A=5^10.16 /5^9.16
A=5^9.5.16/5^9.16
=>A=5/1
=>A=1
B=2^10.55+2^10. 26 / 2^8 . 27
B=2^10.(55+26) / 2^8 .27
B=2^10.81 / 2^8 .27
B=2^8.2^2.81 / 2^8.27
=>B=2^2.81 / 27
=>B=4.81 / 27
=>B=4.3^3.3 / 3^3
=>B=4.3
=>B=12
Cn phần C thì....mik chưa rõ lém nhưng mak nếu ai cko mik là dzui lém òy......ủng hộ nhoa mina
\(\frac{2}{1}\cdot3\cdot\frac{2}{3}\cdot5\cdot\frac{2}{5}\cdot7\cdot\frac{2}{7}\cdot9\cdot\frac{2}{9}\cdot11\)
\(=2\cdot\left(3\cdot\frac{2}{3}\right)\cdot\left(5\cdot\frac{2}{5}\right)\cdot\left(7\cdot\frac{2}{7}\right)\cdot\left(9\cdot\frac{2}{9}\right)\cdot11\)
\(=2\cdot2\cdot2\cdot2\cdot2\cdot11\)
\(=352\)
\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)
\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)
\(=\dfrac{2}{5}\times\dfrac{3}{7}\)
\(=\dfrac{6}{35}\)
\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)
\(x+\dfrac{1}{6}=\dfrac{3}{4}\)
\(x=\dfrac{9}{12}-\dfrac{2}{12}\)
\(x=\dfrac{7}{12}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)
\(\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)
\(\dfrac{1}{2020}+x=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}-\dfrac{1}{2020}\)
\(x=\dfrac{1010}{2020}-\dfrac{1}{2020}\)
\(x=\dfrac{1009}{2020}\)
\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)
\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)
\(=\dfrac{2}{5}\times\dfrac{3}{7}\)
\(=\dfrac{6}{35}\)
\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)
\(\Rightarrow\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}-x\)
\(\Rightarrow\dfrac{3}{4}-x=\dfrac{1}{6}\)
\(\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{7}{12}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1\times2\times3\times4\times...\times2019}{2\times3\times4\times5\times...\times2020}+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2020}+x=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{2}-\dfrac{1}{2020}=\dfrac{1009}{2020}\)
bằng 5238
bằng 5238