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\(=\left[3^{22}. 3^5+2.3^{27}\right]:3^{26}\)
\(=\left[3^{27}+2.3^{27}\right]:3^{26}\)
\(=\left[3^{27}.\left(1+2\right)\right]:3^{26}\)
\(=\left[3^{27}.3\right]:3^{26}\)
\(=3^{28}:3^{26}\)
\(=3^2\)
\(\left[3^{22}\cdot\left(3^8:3^3\right)+2\cdot3^{27}\right]:3^{26}\\ =\left(3^{22}\cdot3^5+2\cdot3^{27}\right):3^{26}\\ =3^{27}\left(1+2\right):3^{26}\\ =3^{27}\cdot3:3^{26}\\ =3^2=9\)
\(\left[3^{22}.\left(3^8:3^3\right)+2.3^{27}\right]\):\(3^{26}\)
=\(\left(3^{22}.3^5+2.3^{27}\right):3^{26}\)
=(\(3^{27}\)+2.\(3^{27}\)):\(3^{26}\)
=\(3^{27}\).(1+2):\(3^{26}\)
=\(3^{28}:3^{26}=3^2\)=9
Ta có :\(\frac{3^2.3^8}{27^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{\left(3^3\right)^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{3^9}=3^x\)
\(\Rightarrow3^1=3^x\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
\(\frac{3^2.3^8}{27^3}=3^x\)
\(\Leftrightarrow\frac{3^{2+8}}{\left(3^3\right)^3}=3^x\)
\(\Leftrightarrow\frac{3^{10}}{3^9}=3^x\)
\(\Leftrightarrow3=3^x\)
\(\Leftrightarrow x=1\)
\(\frac{3^2.3^8}{37^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{\left(3^3\right)^3}=3^x\Rightarrow\frac{3^{10}}{3^9}=3^x\Rightarrow3^1=3^x\Rightarrow x=1\)
2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35 18/27 - 2/6=1/3 37/12 - 3=1/12
11/9 x 3/22=1/6 7/13 x 13/7=1 4 x6/7=24/7
2/5 : 3/10=4/3 3/8 : 9/4=1/6 8/21 : 4/7=2/3
\(\frac{3^2.3^8}{\left(3^3\right)^3}=3^x\frac{3^{10}}{3^9}=3^x3^{10-9}=3^x3^x=3x=1\)
\(\dfrac{3^2.3^8}{27^3}\)
\(=\dfrac{3^2.3^8}{\left(3^3\right)^3}\)
\(=\dfrac{3^2.3^8}{3^9}\)
\(=\dfrac{3^{10}}{3^9}\)
\(=3^1=3\)
\(3=3x\)
\(x=3:3\)
\(x=1\)
\(\frac{11.3^{22}.3^7-9^{15}}{2^2.3^{28}}=\frac{11.3^{29}}{2^2.3^{28}}-\frac{3^{30}}{2^2.3^{28}}=\frac{11.3}{4}-\frac{9}{4}=\frac{33-9}{4}=\frac{24}{4}=6\)
\(\frac{27^5.8^2-9^7.4^3}{2^6.9^6}=\frac{3^{15}.2^6}{2^6.3^{12}}-\frac{3^{14}.2^6}{2^6.3^{12}}=27-9=18\)
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