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\(=\left[3^{22}. 3^5+2.3^{27}\right]:3^{26}\)
\(=\left[3^{27}+2.3^{27}\right]:3^{26}\)
\(=\left[3^{27}.\left(1+2\right)\right]:3^{26}\)
\(=\left[3^{27}.3\right]:3^{26}\)
\(=3^{28}:3^{26}\)
\(=3^2\)
\(\left[3^{22}\cdot\left(3^8:3^3\right)+2\cdot3^{27}\right]:3^{26}\\ =\left(3^{22}\cdot3^5+2\cdot3^{27}\right):3^{26}\\ =3^{27}\left(1+2\right):3^{26}\\ =3^{27}\cdot3:3^{26}\\ =3^2=9\)
\(\left[3^{22}.\left(3^8:3^3\right)+2.3^{27}\right]\):\(3^{26}\)
=\(\left(3^{22}.3^5+2.3^{27}\right):3^{26}\)
=(\(3^{27}\)+2.\(3^{27}\)):\(3^{26}\)
=\(3^{27}\).(1+2):\(3^{26}\)
=\(3^{28}:3^{26}=3^2\)=9
\(\frac{11.3^{22}.3^7-9^{15}}{2^2.3^{28}}=\frac{11.3^{29}}{2^2.3^{28}}-\frac{3^{30}}{2^2.3^{28}}=\frac{11.3}{4}-\frac{9}{4}=\frac{33-9}{4}=\frac{24}{4}=6\)
\(\frac{27^5.8^2-9^7.4^3}{2^6.9^6}=\frac{3^{15}.2^6}{2^6.3^{12}}-\frac{3^{14}.2^6}{2^6.3^{12}}=27-9=18\)
~ Học tốt ~
a: \(=47-\left[\left(45\cdot16-25\cdot12\right):14\right]\)
\(=47-30=17\)
b: \(=50-\left[6+34\right]\)
=50-40
=10
Help me plsss
Ko biết