Tính nhanh
a . 321 + ( − 15 ) + [ 30 + ( − 321 ) ] b . ( 2018 + 432 ) + [ 168 + ( − 2018 ) ]
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)=321+15+30+(-321)
=[321+(-321)]+(15+30)
=0+45=45
b)=2016+432+168+(-2016)
=[2016+(-2016)]+(432+168)
=0+600=600
a)321+{15+[30+(-321)]}=[321+(-321)]+(15+30)=0+45=45
b)(2016+432)+[168+(-2016)]=[2016+(-2016)]+(432+168)=0+600=600
321 + { -15 + [ 30 + (-321) ] }
= 321 + { -15 + [ 30 - 321 ] }
= 321 + { -15 + 30 - 321 }
= 321 - 15 + 30 - 321
= (321 - 321) - (15 - 30)
= 0 - (-15)
= 15
(2016 + 432) + [168 + (-2016) ]
= 2016 + 432 + [ 168 - 2016 ]
= 2016 + 432 + 168 - 2016
= (2016 - 2016) + (432 + 168)
= 0 + 600
= 600
minh khong biet dau minh chi moi lop 5 thoi
chuc ban nam moi vui ve
thank you very much
\(\text{14-(-15)-21}\)
\(=14+15-21\)
\(=29-21\)
\(=8\)
\(321+\left\{-15+\left[30+\left(-321\right)\right]\right\}\)
\(=321+\left(-15\right)+30+\left(-321\right)\)
\(=\left(321+\left(-321\right)\right)+\left(\left(-15\right)+30\right)\)
\(=0+15\)
\(=15\)
\(\text{(2016+432)+[168+(-2016)]}\)
\(=2016+432+168+\left(-2016\right)\)
\(=\left[2016+\left(-2016\right)\right]+\left(432+168\right)\)
\(=0+600\)
\(=600\)
học tốt
b,
\(B=\frac{2018+2019}{2019+2020}=\frac{2018}{2019+2020}+\frac{2019}{2019+2020}\)
Ta thấy :
\(\frac{2018}{2019}>\frac{2018}{2019+2020}\)
\(\frac{2019}{2020}>\frac{2019}{2019+2020}\)
Từ đó , suy ra :
\(\frac{2018}{2019}+\frac{2019}{2020}>\frac{2018+2019}{2019+2020}\)
Vậy...
#Louis
Ta có :
\(\frac{205}{321}< \frac{205}{315}\)
\(\frac{214}{315}>\frac{205}{315}\)
\(\Leftrightarrow\frac{205}{321}< \frac{214}{315}\)
a, ( -2009 ) - ( 234 - 2009 )
b, ( 134 - 167 + 45 ) - ( 134 + 45 )
c, 321 + { -15 + [ 30 + ( -321 ) ]}
1.a) 168 - 300 : 15
= 168 - 20 = 148
b) 103 - 13 = 90
2. 87 - (321 - x) = 75 : 5 = 15
321 - x = 87 - 15
321 - x = 72
x = 321 - 72 = 249