Tìm số nguyên x biết:
a) x:(-9) = -54
b) x:(-12) = 18
c) x:(-5) = -19
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a: x:(-9)=-54
=>\(x=\left(-54\right)\cdot\left(-9\right)\)
=>\(x=54\cdot9=486\)
b: \(x:\left(-12\right)=18\)
=>\(x=18\cdot\left(-12\right)=-216\)
c: \(x:\left(-5\right)=-19\)
=>\(x:5=19\)
=>\(x=19\cdot5=95\)
d: \(\left(x-28\right):\left(-12\right)=-5\)
=>\(x-28=\left(-12\right)\cdot\left(-5\right)=60\)
=>x=60+28=88
e: \(\left(x+15\right):\left(-28\right)=8\)
=>x+15=-28*8=-224
=>x=-224-15=-239
f: (x+30):(-45)=-4
=>\(x+30=\left(-45\right)\cdot\left(-4\right)=180\)
=>x=180-30
=>x=150
a) x : (-9) = -54
x= -54 . (-9)= 486
________
b) x : (-12) = 18
x= 18. (-12)= -216
_________
c) x : (-5) = -19
x= (-19). (-5)= 95
__________
d) (x - 28) : (-12) = -5
(x-28)= (-5). (-12)= 60
x= 60+28= 88
_______
e) (x + 15) : (-28) = 8
(x+15)= 8. (-28)= -224
x= -224 - 15 = - 239
__________
f) (x + 30) : (-45) = -4
(x+30)= -4. (-45)= 180
x= 180 - 30=150
a: =>y/15=-2/3
hay y=-10
b: 2/x=x/18
nên \(x^2=36\)
hay \(x\in\left\{6;-6\right\}\)
c: x/9=16/x
nên \(x^2=144\)
hay \(x\in\left\{12;-12\right\}\)
`A)2/3=x/60`
`=>40/60=x/60`
`=>x=40`
`B)-1/2=y/18`
`=>-9/18=y/18`
`=>y=-9`
`C)3/x=y/35=-36/84`
Mà `-36/84=(-3 xx 12)/(7 xx 12)=-3/7`
`=>3/x=-3/7`
`=>x=-7`
`y/35=-3/7=-15/35`
`=>y=-15`
`D)7/x=y/27=-42/54`
Mà `-42/54=(-7 xx 6)/(9 xx 6)=-7/9`
`=>7/x=-7/9`
`=>x=-9`
`y/27=-7/9=-21/27`
`=>y=-21`
\(a,\Rightarrow x^3+9x^2+27x+27-9x^3-6x^2-x+8x^3+1-3x^2=54\\ \Rightarrow26x=26\Rightarrow x=1\\ b,\Rightarrow x^3-9x^2+27x-27-x^3+27+6x^2+12x+6+3x^2=-33\\ \Rightarrow39x=-39\Rightarrow x=-1\)
\(a,\Leftrightarrow x=7-4=3\\ b,\Leftrightarrow2x=-18+5=-13\\ \Leftrightarrow x=-\dfrac{13}{2}\\ c,\Leftrightarrow x-21=10\\ \Leftrightarrow x=31\\ d,\Leftrightarrow-12-x+19=0\\ \Leftrightarrow7-x=0\\ \Leftrightarrow x=7\)
a, <=> x=7-4
<=> x=3
b, 2x= -18 +5
<=>2x=-13
<=> x= -13/2
c, <=> x -21=-10
<=> x= -10 +21
<=> x=11
d, <=> -12+19 -x=0
<=> 7-x=0
<=> x=7
a) \(\left(2x+3\right)\left(y-1\right)=54\)
\(\Rightarrow2x+3,y-1\inƯ\left(54\right)\)
Ta có bảng sau:
2x + 3 | 54 | 1 | -1 | -54 | 2 | -2 | 27 | -27 | -9 | 9 | 6 | -6 | 18 | -18 | -3 | 3 |
y - 1 | 1 | 54 | -54 | -1 | 27 | -27 | 2 | -2 | -6 | 6 | 9 | -9 | 3 | -3 | -18 | 18 |
x | 51/2 | -1 | -2 | -57/2 | -1/2 | -5/2 | 12 | -15 | -6 | 3 | 3/2 | -9/2 | 15/2 | -21/2 | -3 | 0 |
y | 2 | 55 | -53 | 0 | 28 | -26 | 3 | -1 | -5 | 7 | 10 | -8 | 4 | -2 | -17 | 19 |
Vậy: ...
a: =>19/23>19/x>19/29
=>\(x\in\left\{24;25;26;27;28\right\}\)
b: =>88/132<88/x<88/128
=>132>x>128
=>\(x\in\left\{131;130;129\right\}\)
c: =>\(\left\{{}\begin{matrix}\dfrac{4}{x}-\dfrac{x}{8}< 0\\\dfrac{x}{8}-\dfrac{5}{x}< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{32-x^2}{8x}< 0\\\dfrac{x^2-40}{8x}< 0\end{matrix}\right.\)
=>32<x^2<40
=>x=6
a ) x : − 9 = − 54 x = − 54 . − 9 x = 486
b ) x : − 12 = 18 x = 18 . − 12 x = − 216
c ) x : − 5 = − 19 x = − 19 . − 5 x = 95