Tính giá trị các biểu thức sau: C = 11 12 : 33 16 . 3 5
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\(A=\dfrac{5}{11}.\dfrac{5}{7}+\dfrac{5}{11}.\dfrac{2}{7}+\dfrac{6}{11}=\dfrac{5}{11}\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\dfrac{6}{11}=\dfrac{5}{11}.1+\dfrac{6}{11}=\dfrac{5}{11}+\dfrac{6}{11}=\dfrac{11}{11}=1\)
\(B=\dfrac{3}{13}.\dfrac{6}{11}+\dfrac{3}{13}.\dfrac{9}{11}-\dfrac{3}{13}.\dfrac{4}{11}=\dfrac{3}{13}\left(\dfrac{6}{11}+\dfrac{9}{11}-\dfrac{4}{11}\right)=\dfrac{3}{13}.1=\dfrac{3}{13}\)
\(C=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right).0=0\)
a) {132 - [116- (16 - 8)]:2}.5
= [132 - (116 - 8): 2] .5
= (132 - 108 : 2). 54
= (132 - 54).5
= 78.5 = 390
b) 36: {136 : 200 - (12+ 8. 20)]}
= 36: {336 : [200 - ( 12 + 160)]}
= 36 : [336 : ( 200 - 172)
= 36 : ( 336 : 28) = 3
c) 86 - [15. (64 - 39): 75+11]
= 86 - (15.25 : 75 + 11)
= 86 - ( 5 + 11)
= 70
d) 55 - [ 49 - ( 2 3 . 17 - 2 3 . 14 ) ]
= 55 - 49 - 2 3 . 3
= 55- ( 49 - 24)
= 30
a) {132 – [116 – (16 – 8)]:2}.5
= [132 – (116 – 8): 2] .5
= (132 – 108 : 2). 5
= (132 –54).5
= 78.5 = 390
b) 36: {136 : 200 – (12+ 8. 20)]}
= 36: {336 : [200 – ( 12 + 160)]}
= 36 : [336 : ( 200 – 172)
= 36 : ( 336 : 28)
= 36 : 12 = 3
c) 86 – [15. (64 - 39): 75+11]
= 86 – (15.25 : 75 + 11)
= 86 – ( 5 + 11)
= 70.
d) 55 – [49 – (23 . 17 – 23.14)]
= 55 – (49 – 23 .3)
= 55 – ( 49 – 24)
= 30
a) \(A=\left(\dfrac{3}{4}:\dfrac{2}{3}\right):\dfrac{3}{5}=\left(\dfrac{3}{4}\cdot\dfrac{3}{2}\right)\cdot\dfrac{5}{3}=\dfrac{9}{8}\cdot\dfrac{5}{3}=\dfrac{15}{8}\)
b) \(B=\dfrac{3}{4}:\left(\dfrac{2}{5}:\dfrac{3}{5}\right)=\dfrac{3}{4}:\left(\dfrac{2}{5}\cdot\dfrac{5}{3}\right)=\dfrac{3}{4}:\dfrac{2}{3}=\dfrac{3}{4}\cdot\dfrac{3}{2}=\dfrac{9}{8}\)
c) \(C=\left(\dfrac{11}{12}:\dfrac{33}{16}\right)\cdot\dfrac{3}{5}=\left(\dfrac{11}{12}\cdot\dfrac{16}{33}\right)\cdot\dfrac{3}{5}=\dfrac{4}{9}\cdot\dfrac{3}{5}=\dfrac{4}{15}\)
a.
A=\(\left(\dfrac{3}{4}:\dfrac{2}{3}\right):\dfrac{3}{5}\)
=\(\left(\dfrac{3}{4}.\dfrac{3}{2}\right):\dfrac{3}{5}\)
=\(\dfrac{9}{8}:\dfrac{3}{5}\)
=\(\dfrac{9}{8}.\dfrac{5}{3}=\dfrac{45}{24}=\dfrac{15}{8}\)
b.
B=\(\dfrac{3}{4}:\left(\dfrac{2}{5}:\dfrac{3}{5}\right)\)
=\(\dfrac{3}{4}:\left(\dfrac{2}{5}.\dfrac{5}{3}\right)\)
=\(\dfrac{3}{4}:\dfrac{2}{3}=\dfrac{3}{4}.\dfrac{3}{2}\)
=\(\dfrac{9}{8}\)
c.
C=\(\left(\dfrac{11}{12}:\dfrac{33}{16}\right).\dfrac{3}{5}\)
=\(\left(\dfrac{11}{12}.\dfrac{16}{33}\right).\dfrac{3}{5}\)
=\(\dfrac{4}{9}.\dfrac{3}{5}=\dfrac{12}{45}\)
=\(\dfrac{4}{15}\)
b, \(\dfrac{4}{9}\) + \(\dfrac{6}{11}\) + \(\dfrac{5}{9}\) + \(\dfrac{16}{11}\) + 7
= (\(\dfrac{4}{9}\) + \(\dfrac{5}{9}\)) + (\(\dfrac{6}{11}\) + \(\dfrac{16}{11}\)) + 7
= 1 + 2 + 7
= 10
a, Đáng lẽ đề phải là:
0,2 x 517 x 7 + 0,7 x 483 x 2 em ạ