Thực hiện các phép tính:
d ) D = ( 5 x 3 + 14 x 2 + 12 x + 8 ) : ( x + 2 )
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Bài 1:
b: \(=\dfrac{x+3-4-x}{x-2}=\dfrac{-1}{x-2}\)
Bài 2:
a: \(=\dfrac{x+1}{2\left(x+3\right)}+\dfrac{2x+3}{x\left(x+3\right)}\)
\(=\dfrac{x^2+x+4x+6}{2x\left(x+3\right)}=\dfrac{x^2+5x+6}{2x\left(x+3\right)}=\dfrac{x+2}{2x}\)
d: \(=\dfrac{3}{2x^2y}+\dfrac{5}{xy^2}+\dfrac{x}{y^3}\)
\(=\dfrac{3y^2+10xy+2x^3}{2x^2y^3}\)
e: \(=\dfrac{x^2+2xy+x^2-2xy-4xy}{\left(x+2y\right)\left(x-2y\right)}=\dfrac{2x^2-4xy}{\left(x+2y\right)\cdot\left(x-2y\right)}=\dfrac{2x}{x+2y}\)
Bài 1:
a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)
\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{3}\)
\(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)
\(\dfrac{1}{4}\) \(x\)= \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)
\(\dfrac{1}{4}x=\dfrac{11}{24}\)
\(x=\dfrac{11}{24}:\dfrac{1}{4}\)
\(x=\dfrac{11}{24}\times4\)
\(x=\dfrac{11}{6}\)
b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)
\(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)
\(x\) = \(\dfrac{9}{10}\)
a) \(\dfrac{-5}{9}-\dfrac{-5}{12}=\dfrac{-5}{9}+\dfrac{5}{12}=\dfrac{-20}{36}+\dfrac{15}{36}=-\dfrac{5}{36}\)
b) \(\dfrac{-5}{12}:\dfrac{15}{4}=\dfrac{-5}{12}\times\dfrac{4}{15}=\dfrac{-1}{9}\)
c) \(\dfrac{1}{13}\cdot\dfrac{8}{13}+\dfrac{5}{13}\cdot\dfrac{1}{13}-\dfrac{14}{13}=\dfrac{1}{13}\cdot\left(\dfrac{8}{13}+\dfrac{5}{13}\right)-\dfrac{14}{13}=\dfrac{1}{13}\cdot1-\dfrac{14}{13}=\dfrac{1}{13}-\dfrac{14}{13}=-1\)
1, Thực hiện phép tính
a, (-23).(-3).(+4).(-7)
=69.(-28)
=(-1932)
b, 2.8.(-14).(-3)
=16.42
=672
2, Tìm x
a, 2436 : x = 12 b, 6. x - 5 = 613
x =2436 : 12 6. x = 613 + 5 = 618
x = 203 x =618 : 6 = 103
c, 12. (x - 1) = 0 d, 0 : x = 0
x - 1 = 12 : 0 = 0 x = 0 : 0
x = 0 + 1 = 1 x = 0
1.
a) \(\left(-23\right).\left(-3\right).4.\left(-7\right)=[\left(-23\right).\left(-3\right).\left(-7\right)].4\)
\(=-483.4=-1932\)
b) \(=16.42=672\)
2.
a) \(\Rightarrow x=2436\div12=203\)
b) \(\Rightarrow6x=618\Rightarrow x=103\)
c) \(\Rightarrow x-1=0\Rightarrow x=1\)
d) Ko có gtr nào của x thỏa mãn 0:x=0
~ HỌC TỐT ~
# Q.TRANG #
Bài 2:
a: =>x-35=-23
=>x=12
b: =>|x-8|=13
=>x-8=13 hoặc x-8=-13
=>x=21 hoặc x=-5
Bài 1:
a: =42-98-42+12-12=-98
b: =10x4x3x(-25)=40x(-25)x3=-1000x3=-3000
a)(-12)+(-9)+112+|-30|
=(-21)+112+30
= 91+ 30
=121
b) - 2015 + (-268)+(-201)+168+301
=(-2283)+(-33)+301
=(-2316)+301
= - 2015
c)160 :{|-17|+[3x2x5-(14+2x11:2x8)]}
= 160 :{17+[3x2x5-(14+22:16)]}
=160:{17+[ 3x2x5-15,375]
=160:{17+30-15,375}
=160:31,625
=5,05
`!`
`(x^3-3x^2):(x-3)`
`= x^2(x-3) :(x-3)`
`=x^2`
`----`
`(2x^2+2x-4):(x+2)`
`=2(x^2+x-2) :(x+2)`
`= 2 (x^2+2x-x-2) :(x+2)`
\(=2\left[x\left(x+2\right)-\left(x+2\right)\right]:\left(x+2\right)\)
`= 2(x+2)(x-1) :(x+2)`
`=2(x-1)`
`-------`
`(x^4-x-14):(x-2)`
https://hoc24.vn/cau-hoi/x4-x-14-x-2-giup-minh.204306769717
bn tham khảo ở đây nha
`----`
`(x^3-3x^2+x-3):(x-3)`
`= x^2(x-3) +(x-3) :(x-3)`
`=(x-3)(x^2+1):(x-3)`
`=x^2+1`
a, (-25) + 276 - (276 - 25)
= (-25) + 276 - 276 + 25
= [ (-25) + 25] - (276 - 276)
= 0 - 0
= 0
b, 24 x 46 + 24 x 53 + 24
= 24 x ( 46 + 53 + 1)
= 24 x 100
= 2400
Vậy (5x3 + 14x2 + 12x + 8):(x + 2) = 5x2 + 4x + 4