Question

[@@Hiếu Lợn Pro@@]

Tìm x, biết:

(x-0,3)²=0,(4)

Answer 1

[Vũ Minh Tuấn]

\(\left(x-0,3\right)^2=0,\left(4\right)\)

\(\Rightarrow\left(x-\frac{3}{10}\right)^2=\frac{4}{9}\)

\(\Rightarrow\left(x-\frac{3}{10}\right)^2=\left(\pm\frac{2}{3}\right)^2\)

\(\Rightarrow x-\frac{3}{10}=\pm\frac{2}{3}.\)

\(\Rightarrow\orbr{\begin{cases}x-\frac{3}{10}=\frac{2}{3}\\x-\frac{3}{10}=-\frac{2}{3}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{2}{3}+\frac{3}{10}\\x=\left(-\frac{2}{3}\right)+\frac{3}{10}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{29}{30}\\x=-\frac{11}{30}\end{cases}}\)

Vậy \(x\in\left\{\frac{29}{30};-\frac{11}{30}\right\}.\)

Chúc bạn học tốt!

Answer 2

[⚽๖ۣۜTrần ๖ۣۜQuốc🏆๖ۣۜDũng🥇||✅]

\(\left(x-0,3\right)^2=0,\left(4\right)\)

\(\left(x-0,3\right)^2=\frac{4}{9}\)

\(\Rightarrow\left(x-0,3\right)^2=\left(\frac{2}{3}\right)^2\) hoặc  \(\left(x-0,3\right)^2=\left(\frac{-2}{3}\right)^2\)

\(\Rightarrow x-0,3=\frac{2}{3}\)                 hoặc   \(x-0,3=\frac{-2}{3}\)           

     \(x=\frac{2}{3}-0,3\)                             \(x=\frac{-2}{3}-0,3\)

     \(x=\frac{11}{30}\)                                        \(x=\frac{-29}{30}\)

                          Vậy \(x\in\left\{\frac{11}{30};\frac{-29}{30}\right\}\)