Tính hợp lý(nếu có thể)
a)67+(-2018)+33+2018-189
b)(1974+647)-(1974-53)
c)105-301+(-129)-(-255)
d)-(-229)+(-219)-401+12
e)666-(-422)-100-80
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a.67+( -2018)+33+2018-189
=[(-2018)+2018]+(67+33)-189
=0+100-189
=100-189
= -89
Trl:
d) \(555-\left(-33\right)-100-80\)
\(=588-20\)
\(=568\)
e) \(-\left(-229\right)+\left(-219\right)-401+12\)
\(=10-413\)
\(=403\)
f) \(300-\left(-200\right)-\left(-120\right)+18\)
\(=500-\left(-102\right)\)
\(=602\)
Hc tốt
a) = (-15)+(-10)
= -25
b) = (-222)-100-80
= (-322)-80
= -402
c) = 229+219-401+12
= 448-401+12
=47+12
= 59
d) = 500-(-120)+18
= 620+18
= 638
A. -25
B. 708
C. -379
D. 638
Mình chỉ ghi kết quả thôi ! Bạn biết cách tính chứ!
Giải:
\(A=\left[\left(-8\right)+\left(-7\right)\right]+\left(-10\right)=\left(-15\right)+\left(-10\right)=\left(-25\right)\)
\(B=-\left(-299\right)+\left(-219\right)+\left(-401\right)+12=299-219-401+12=-309\)
\(C=555+\left(-100\right)+\left(-80\right)+\left|-333\right|=555-100-80+333=708\)
\(D=\left|-347\right|+\left(-40\right)+3150+\left(-307\right)=347-40+3150-307=2456\)
\(E=98.42-\left\{50.\left[\left(18-2^3\right):2+3^2\right]\right\}\)
\(E=4116-\left\{50.\left[\left(18-8\right):2+9\right]\right\}\)
\(E=4116-\left\{50.\left[10:2+9\right]\right\}\)
\(E=4116-\left\{50.\left[5+9\right]\right\}\)
\(E=4116-\left\{50.14\right\}\)
\(E=4116-700\)
\(E=3416\)
\(F=-80-\left[-130-\left(12-4^2\right)\right]+2008^0\)
\(F=-80-\left[-130-\left(12-16\right)\right]+1\)
\(F=-80-\left[-130-\left(-4\right)\right]+1\)
\(F=-80-\left(-126\right)+1\)
\(F=47\)
\(G=1000+\left(-670\right)+297+\left(-330\right)=1000-670+297-330=297\)
\(H=1024:2^4+140:\left(38+2^5\right)-7^{23}:7^{21}\)
\(H=2^{10}:2^4+140:\left(38+32\right)-7^2\)
\(H=2^6+140:70-49\)
\(H=64+2-49\)
\(H=17\)
\(I=\left|-129\right|-119+\left|2-31\right|=129-119+\left|-29\right|=10+29=39\)
\(K=219+573+381-173\)
\(K=\left(219+381\right)+\left(573-173\right)\)
\(K=600+400\)
\(K=1000\)
\(L=36.33-105.11+22.15\)
\(L=36.33-35.3.11+11.2.3.5\)
\(L=36.33-35.33+33.10\)
\(L=33.\left(36-35+10\right)\)
\(L=33.11\)
\(L=363\)
\(N=160-\left(2^3.5^2-6.25\right)\)
\(N=160-\left[25.\left(8-6\right)\right]\)
\(N=160-\left[25.2\right]\)
\(N=160-50\)
\(N=110\)
\(O=\left(44.52.60\right):\left(11.13.15\right)=137280:2145=64\)
\(P=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).\left(2^4-4^2\right)=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).0=0\)
\(Q=100+98+96+...+4+2-97-95-...-3-1\)
\(Q=100+\left(98-97\right)+\left(96-95\right)+...+\left(4-3\right)+\left(2-1\right)\)
\(Q=100+1+1+...+1+1\)
Vì có 98:2=49 số 1
\(\Rightarrow Q=100+49\)
\(Q=149\)
d ( 1-1/2)x(1-1/3)x(1-1/4)x......x(1-1/2018)
= 1/2x2/3x3/4x...x2017/2018
=\(\frac{1x2x3x....x2017}{2x3x4x....x2018}\)
= \(\frac{1}{2018}\)
e , 1+4+7+...+100
= dãy có số số hạng là
(100-1):3+1=34 ( số số hạng)
tổng là : (100+1 ) x 34 : 2 =1717
=>1717
\(\left(-8\right)+\left(-7\right)+\left(-10\right)\)
\(=-8-7-10\)
\(=-15-10=-25\)
\(\left(-229\right)+219-401+12\)
\(=\left(219-229\right)-401+12\)
\(=-10-401+12\)
\(=-399\)
\(555-\left(-333\right)-100-80\)
\(=555+333-100-80\)
\(=888-100-80\)
\(=780-80=700\)
\(300-\left(-200\right)-\left(-120\right)+18\)
\(=300+200+120+18\)
\(=500+120+18\)
\(=620+18\)
\(=638\)
coppy trên mạng hay tự làm đó bạn