Tìm x, biết
x+9/x+6= (x+6)+3/ x+6
giúp mik với
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\(ƯC\left(18,54\right)=Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\\ \Rightarrow x\in\left\{9;18\right\}\)
\(a,\dfrac{3}{4}:\dfrac{6}{x}=\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{4}:\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{5}\\ x=6:\dfrac{3}{5}\\ x=10\\ b,\left(x+\dfrac{7}{4}\right)\times\dfrac{2}{3}=6\\ x+\dfrac{7}{4}=6:\dfrac{2}{3}\\x+\dfrac{7}{4}=9\\ x=9-\dfrac{7}{4}\\ x=\dfrac{29}{4}\)
a) 6/-x=x/-24
=> -x.x=6.-24
=>-x.x=-144
=>x=12 hay x=-12
b)9/x=-35/105
=>9/x=-1/3
=>x=9.3/-1=-27
=>x=-27
c)x-1/8=5/8
=>x=5/8+1/8
=>x=3/4
d)x-1/2-(3/2+x)=-2
=>-x+4/2=-2
=>-x/2=0
=>x=0
e)x+1/3=-12/5.10/6
x+1/3=-4
x=-4-1/3
x= -13/3
#YM
15/8−4/9×6/8+1/6=15/8−24/72+1/6=15/8−1/3+1/6
=45/24−8/24+4/24=(45−8+4)/24=41/24
Ta có: \(\left(x^{3n}+y^{3n}\right)\left(x^{3n}-y^{3n}\right)=-x^6-y^6\)
\(\Leftrightarrow x^{6n}-y^{6n}=-x^6-y^6\)
\(\Leftrightarrow\left\{{}\begin{matrix}n=-1\\n=1\end{matrix}\right.\Leftrightarrow n\in\varnothing\)