Question

[Đông Viên]

cho a.b>0 (a+b<=1) tim GTNN cua N=\(\sqrt{a+b}\sqrt{\frac{1}{a}+\frac{1}{b}}\)

Answer 1

[Vũ Huy Hoàng]

\(\sqrt{a+b}.\sqrt{\frac{1}{a}+\frac{1}{b}}=\sqrt{\left(a+b\right)\left(\frac{1}{a}+\frac{1}{b}\right)}\)

\(=\sqrt{2+\frac{a}{b}+\frac{b}{a}}\ge\sqrt{2+2\sqrt{\frac{a}{b}.\frac{b}{a}}}=\sqrt{2+2}=2\)

Dấu bằng xảy ra khi a = b.