ccác cậu ơi giúp tớ hai bài dưới với t sắp p nộp r huhu
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H
hằng
19 tháng 7 2019
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C
0
GL
1 tháng 8 2023
1. shouldn't
2. should
3. should
4. should
5. should
6. Should
7. should
8. shouldn't
9. should
10. should
11. shouldn't
12. Should
13. should
14. shouldn't
15. shouldn't
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II
1. was -> were
2. Was -> Were
3. was -> did
4. went -> go
5. weren't -> didn't
6. have -> had
7. broke -> break
8. go -> went
9. am -> was
10. turn -> turned
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III
1. taught/ to ride/ was
2. does your father go/ drives
3. are going
4. used/ lived
5. spent/ repairing
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IV
1. Lang Lieu couldn't buy any special food because he was very pool
2. During Tet, Vietnamese people buy all kinds of sweets, so they make Chung cakes as well
3. The Hung King Temple Festival was a local festival. However, it has become a public holiday in Viet Nam
4. At the Mid-Autumn festival, kids can sing, dance and enjoy moon cakes; therefore, every child like it very much.
5. Because the water is highly polluted, we can't swim in this part of the river
6. Mr. Minh is admired since he dedicates all his life to protecting the environment
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V
1. A
2. B
3. A
4. D
5. C
T
3
22 tháng 6 2021
Bài 1:
a) \(\dfrac{4}{5}-\dfrac{7}{6}+\dfrac{-6}{15}=\dfrac{24}{30}-\dfrac{35}{30}+\dfrac{-12}{30}=\dfrac{24-35+-12}{30}=\dfrac{-23}{30}\)
b) \(\dfrac{-5}{9}.\dfrac{7}{13}+\dfrac{6}{13}.\dfrac{-5}{9}+3\dfrac{7}{9}\)
\(=\dfrac{-5}{9}.\left(\dfrac{7}{13}+\dfrac{6}{13}\right)+\dfrac{34}{9}\)
\(=\dfrac{-5}{9}.1+\dfrac{34}{9}\)
\(=\dfrac{-5}{9}+\dfrac{34}{9}\)
\(=\dfrac{29}{9}\)
c) \(6\dfrac{3}{8}-\left(4\dfrac{3}{8}-\dfrac{1}{2}\right)=\dfrac{51}{8}-\dfrac{35}{8}+\dfrac{1}{2}=\left(\dfrac{51}{8}-\dfrac{35}{8}\right)+\dfrac{1}{2}=2+\dfrac{1}{2}=\dfrac{5}{2}\)
d) \(2\dfrac{1}{3}.1,5-\left(\dfrac{11}{10}+50\%\right):\dfrac{4}{15}\)
\(=\dfrac{7}{3}.1,5-\dfrac{8}{5}:\dfrac{4}{15}\)
\(=\dfrac{7}{2}-6\)
\(=\dfrac{-5}{2}=-2,5\)
LM
2
13 tháng 12 2021
\(B=\dfrac{10\cdot9}{\sqrt{10}}-2\cdot5+1+2021=9\sqrt{10}-10+2022=9\sqrt{10}+2012\)
LM
1
AH
Akai Haruma
Giáo viên
13 tháng 12 2021
Lời giải:
Nếu $x+y+z+t=0$ thì $M=\frac{-t}{t}=\frac{-x}{x}=\frac{-z}{z}=-1$
$\Rightarrow (M-1)^{2025}=(-1-1)^{2025}=(-2)^{2025}$
Nếu $x+y+z+t\neq 0$. Áp dụng TCDTSBN:
$M=\frac{x+y+z}{t}=\frac{y+z+t}{x}=\frac{z+t+x}{y}=\frac{t+x+y}{z}=\frac{x+y+z+y+z+t+z+t+x+t+x+y}{t+x+y+z}=\frac{3(x+y+z+t)}{x+y+z+t}=3$
$\Rightarrow (M-1)^{2025}=2^{2025}$