Tìm a, biết :
a + 1 + 2 + 3 = 10
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\(\Rightarrow3A=3+3^2+3^3+...+3^{11}\\ \Rightarrow3A-A=\left(3+3^2+...+3^{11}\right)-\left(1+3+...+3^{10}\right)\\ \Rightarrow2A=3^{11}-1\\ \Rightarrow2A+1=3^{11}=3^n\\ \Rightarrow n=11\)
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Bài 1 :
a) \(xy-2x+2y=10\)
\(\Leftrightarrow x\left(y-2\right)+2y=10\)
\(\Leftrightarrow x\left(y-2\right)+2y-4=6\)
\(\Leftrightarrow x\left(y-2\right)+2\left(y-2\right)=6\)
\(\Leftrightarrow\left(x+2\right)\left(y-2\right)=6\)
Ta có : \(x+2\ge2\) vì \(x\in N\)
Do đó : ta có bảng :
x+2 : 2 3 6
y-2 : 3 2 1
x : 0 1 4
y : 5 4 3
Vậy...........
a) \(xy-2x+2y=10\left(x;y\inℕ\right)\)
\(\Rightarrow2xy-4x+4y=20\)
\(\Rightarrow2x\left(y-2\right)+4y-8+8=20\)
\(\Rightarrow2x\left(y-2\right)+4\left(y-2\right)=12\)
\(\Rightarrow\left(2x+4\right)\left(y-2\right)=12\)
\(\Rightarrow\left(2x+4\right);\left(y-2\right)\in\left\{1;2;3;4;6;12\right\}\)
\(\Rightarrow\left(x;y\right)\in\left\{\left(-\dfrac{3}{2};14\right);\left(-1;8\right);\left(-\dfrac{1}{3};6\right);\left(0;5\right);\left(1;3\right);\left(4;3\right)\right\}\)
\(\Rightarrow\left(x;y\right)\in\left\{\left(0;5\right);\left(1;3\right);\left(4;3\right)\right\}\left(x;y\inℕ\right)\)
a) \(A=\frac{7}{10}+\frac{7}{10^2}+\frac{7}{10^3}+...\)
\(A=\frac{777...}{1000...}\)
b) 1/2+1/3+1/4+…+1/63=1/2+(1/3+1/4)+(1/5+1/6+…+1/10)+(1/11+1/12+….+1/20)+(1/21+1/22+….1/63).
Ta thấy:
1/3+1/4>1/4+1/4=1/2
1/5+1/6+…+1/10>5/10=1/2
1/11+1/12+….+1/20>10/20=1/2
Thêm.cái 1/2 sắn có là đủ >2 rồi nhể
a) \(\frac{a}{b}:\frac{2}{3}=\frac{3}{5}-\frac{1}{10}\)
\(\Rightarrow\frac{a}{b}:\frac{2}{3}=\frac{6}{10}-\frac{1}{10}\)
\(\Rightarrow\frac{a}{b}:\frac{2}{3}=\frac{5}{10}\)
\(\Rightarrow\frac{a}{b}=\frac{5}{10}x\frac{2}{3}\)
\(\Rightarrow\frac{a}{b}=\frac{10}{30}\)
\(\Rightarrow\frac{a}{b}=\frac{1}{3}\)
b, \(\frac{a}{b}x\frac{1}{5}=\frac{3}{5}+1\)
\(\Rightarrow\frac{a}{b}x\frac{1}{5}=\frac{3}{5}+\frac{5}{5}\)
\(\Rightarrow\frac{a}{b}x\frac{1}{5}=\frac{8}{5}\)
\(\Rightarrow\frac{a}{b}=\frac{8}{5}:\frac{1}{5}\)
\(\Rightarrow\frac{a}{b}=\frac{8}{5}x5\)
\(\Rightarrow\frac{a}{b}=8\)
a)
b)
Ta có \(\frac{a}{b}=\frac{2}{3}\Rightarrow\frac{a}{2}=\frac{b}{3}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{a}{2}=\frac{b}{3}=\frac{a+b}{2+3}=\frac{10}{5}=2\)
\(\Rightarrow\hept{\begin{cases}a=2\cdot2=4\\b=2\cdot3=6\end{cases}}\)
vậy (a;b)=(4,6)
trả lời
a=10-1-2-3
a=4
vậy....
hok tốt
a + 1 + 2 + 3 = 10
a + 6 = 10
a = 4