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1/ 3-2x+4+6x=x+7+3x
⇔-2x+6x-x-3x=0
⇔0x=0 (Vô số nghiệm)
2/-6(1,5-2x)=3(-15+2x)
⇔-9+12x=-45+6x
⇔6x+36=0
⇔6(x+6)=0
⇔x+6=0
⇔x=-6
Vậy S ϵ {-6}
3/ 3(2x-5)+5(x-1)=4(x+1)
⇔6x-15+5x-5=4x+4
⇔7x=24
⇔x=\(\dfrac{24}{7}\)
Vậy S ϵ {\(\dfrac{24}{7}\)}
1) Ta có: \(3-2x+4+6x=x+7+3x\)
\(\Leftrightarrow4x+7=4x+7\)
\(\Leftrightarrow4x+7-4x-7=0\)
\(\Leftrightarrow0x=0\)(luôn đúng)
Vậy: S={x|\(x\in R\)}
2) Ta có: \(-6\cdot\left(1.5-2x\right)=3\left(-15+2x\right)\)
\(\Leftrightarrow-9+12x=-45+6x\)
\(\Leftrightarrow12x-9+45-6x=0\)
\(\Leftrightarrow6x+36=0\)
\(\Leftrightarrow6x=-36\)
hay x=-6
Vậy: S={-6}
3) Ta có: \(3\left(2x-5\right)+5\left(x-1\right)=4\left(x+1\right)\)
\(\Leftrightarrow6x-15+5x-5=4x+4\)
\(\Leftrightarrow11x-20-4x-4=0\)
\(\Leftrightarrow7x-24=0\)
\(\Leftrightarrow7x=24\)
\(\Leftrightarrow x=\dfrac{24}{7}\)
Vậy: \(S=\left\{\dfrac{24}{7}\right\}\)
\(4-\left(\frac{1}{2}x+\frac{3}{4}\right)=-1,5\)
=> \(\frac{1}{2}x+\frac{3}{4}=4-\left(-1,5\right)\)
=> \(\frac{1}{2}x+\frac{3}{4}=5,5\)
=> \(\frac{1}{2}x=5,5-\frac{3}{4}=\frac{19}{4}\)
=>\(x=\frac{19}{4}:\frac{1}{2}=\frac{19}{2}\)
4-(1/2x+3/4)=-1,5
=>1/2x+3/4=4-(-1,5)
=>1/2x+3/4=5,5
=>1/2x=5,5-3/4
=>1/2x=4,75
=>x=4,75:1/2
=>x=9,5
k cho mình nha
chúc bạn học tốt
c, |2\(x\) + 1| + |3\(x\) - 1| = 0
vì |2\(x\) + 1| ≥ 0; |3\(x\) - 1| = 0
⇒ |2\(x\) + 1| + |3\(x\) - 1| = 0
⇔ \(\left\{{}\begin{matrix}2x+1=0\\3x-1=0\end{matrix}\right.\)
⇔ \(\left\{{}\begin{matrix}2x=-1\\3x=1\end{matrix}\right.\)
\(\Rightarrow\) \(\left\{{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
\(-\dfrac{1}{2}\) < \(\dfrac{1}{3}\)
Vậy \(x\) \(\in\) \(\varnothing\)
a, Nếu 4.|3\(x\) - 1| = |6\(x\) - 2| + |-1,5|
4.|3\(x\) -1| - 2.|3\(x\) - 1| = 1,5
Nếu 3\(x\) - 1 ≥ 0 ⇒ \(x\) ≥ \(\dfrac{1}{3}\)
Ta có: 4.(3\(x\) - 1) - 2.(3\(x\) - 1) = 1,5
12\(x\) - 4 - 6\(x\) + 2 = 1,5
6\(x\) - 2 = 1,5
6\(x\) = 1,5 + 2
6\(x\) = 3,5
\(x\) = 3,5: 6
\(x\) = \(\dfrac{7}{12}\)
Nếu 3\(x\) - 1 < 0 ⇒ \(x\) < \(\dfrac{1}{3}\)
Ta có: - 4.(3\(x\) - 1) = - (6\(x\) - 2) + 1,5
-12\(x\) + 4 + 6\(x\) - 2 = 1,5
-6\(x\) + 2 = 1,5
6\(x\) = 2- 1,5
6\(x\) = 0,5
\(x\) = 0,5 : 6
\(x\) = \(\dfrac{1}{12}\)
Vậy \(x\) \(\in\) {\(\dfrac{1}{12}\); \(\dfrac{7}{12}\)}
a: =>1/3:x=3/5-2/3=9/15-10/15=-1/15
=>x=-1/3:1/15=5
b: \(\Leftrightarrow x\cdot\dfrac{2}{3}-3=\dfrac{2}{5}\cdot\left(-10\right)=-4\)
=>x*2/3=-1
=>x=-3/2
c: =>2x+1=4 hoặc 2x+1=-4
=>x=3/2 hoặc x=-5/2
h: =>x-3=4
=>x=7
g: =>2x-1=3
=>2x=4
=>x=2
f: \(\Leftrightarrow x\cdot\left(\dfrac{3}{2}-\dfrac{7}{3}\right)=\dfrac{3}{2}-\dfrac{2}{3}\)
=>x*-5/6=5/6
=>x=-1
d: =>|2x-1|=3
=>2x-1=3 hoặc 2x-1=-3
=>x=-1 hoặc x=2
1) \(|5x-3|=|7-x|\)
\(\Leftrightarrow\orbr{\begin{cases}5x-3=7-x\\5x-3=x-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}6x=10\\4x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}\)
Vậy...
2) \(2.|3x-1|-3x=7\)
\(\Leftrightarrow2.|3x-1|=7+3x\)
\(\Leftrightarrow\orbr{\begin{cases}2.\left(3x-1\right)=7+3x\\2.\left(3x-1\right)=-7-3x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}6x-2=7+3x\\6x-2=-7-3x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}3x=9\\9x=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=\frac{-5}{9}\end{cases}}\)
Vậy...
\(\frac{2}{3}.x-\frac{3}{2}.\left(x-\frac{1}{2}\right)=\frac{5}{12}\)
\(\Leftrightarrow\frac{2}{3}.x-\frac{3}{2}.x+\frac{3}{4}=\frac{5}{12}\)
\(\Leftrightarrow x.\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}-\frac{3}{4}\)
\(\Leftrightarrow x.\frac{-5}{6}=\frac{-4}{12}\)
\(\Leftrightarrow x=\frac{-4}{12}:\frac{-5}{12}\)
\(\Leftrightarrow x=\frac{4}{5}\)
Vậy : \(x=\frac{4}{5}\)
x= 0,625 hoặc x= 0,875