\(\frac{3}{4}.37\frac{1}{2}-\frac{3}{4}.13\frac{1}{2}\)
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TM
21 tháng 9 2017
\(P=\frac{\frac{3}{7}-\frac{3}{13}+\frac{3}{37}}{\frac{5}{7}-\frac{5}{17}+\frac{5}{37}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{7}{5}-\frac{7}{4}+\frac{7}{3}-\frac{7}{2}}\)
\(=\frac{3\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{37}\right)}{5\left(\frac{1}{7}-\frac{1}{17}+\frac{1}{37}\right)}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{-7\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}\right)}\)
\(=\frac{3}{5}+\frac{1}{-7}\)
\(=\frac{16}{35}\)
Z
25 tháng 7 2019
Lời giải:
Ta có:
\(A=\frac{3}{4}.37\frac{1}{2}-\frac{3}{4}.13\frac{1}{2}=\frac{3}{4}.\left(37\frac{1}{2}-13\frac{1}{2}\right)=\frac{3}{4}.24=18\)
Vậy: \(\frac{3}{4}.37\frac{1}{2}-\frac{3}{4}.13\frac{1}{2}=18\)
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VG
1
BA
18 tháng 12 2018
\(=\frac{3}{8}.37-\frac{3}{8}.13\)
\(=\frac{3}{8}\left(37-13\right)\)
\(=\frac{3}{8}.24\)
\(=9\)
28 tháng 5 2022
a: \(\dfrac{1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}}{1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}}:\dfrac{13+\dfrac{13}{2}+\dfrac{13}{3}+\dfrac{13}{4}}{17-\dfrac{17}{2}+\dfrac{17}{3}-\dfrac{17}{4}}\)
\(=\dfrac{1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}}{1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}}\cdot\dfrac{17\left(1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}\right)}{13\left(1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}\right)}=\dfrac{17}{13}\)
b: \(\dfrac{0.125-\dfrac{1}{5}+\dfrac{1}{7}}{0.375-\dfrac{3}{5}+\dfrac{3}{7}}+\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-0.2}{\dfrac{3}{4}+0.5-\dfrac{3}{10}}\)
\(=\dfrac{\dfrac{1}{8}-\dfrac{1}{5}+\dfrac{1}{7}}{\dfrac{3}{8}-\dfrac{3}{5}+\dfrac{3}{7}}+\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{5}}{\dfrac{3}{4}+\dfrac{3}{6}-\dfrac{3}{10}}\)
\(=\dfrac{1}{3}+\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{5}}{\dfrac{3}{2}\left(\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{5}\right)}=\dfrac{1}{3}+\dfrac{2}{3}=1\)
Ta có:
\(\frac{3}{4}.37\frac{1}{2}-\frac{3}{4}.13\frac{1}{2}\)
=\(\frac{3}{4}.\frac{75}{2}-\frac{3}{4}.\frac{27}{2}\)
=\(\frac{3}{4}.\left(\frac{75}{2}-\frac{27}{2}\right)\)
=\(\frac{3}{4}.24\)
=18
\(\frac{3}{4}\left(37\frac{1}{2}-13\frac{1}{2}\right)\)
\(\frac{3}{4}.24=18\)