Question

[Sao mà xxmangaka]

 Tính nhanh 

A.3/3x6+3/6x9+3/9x12+...+3/93x96+3/96x99

B.1/2x5+1/5x8+1/8x11+...+1/95*98

Answer 1

[나 재민]

\(A=\frac{3}{3.6}+\frac{3}{6.9}+\frac{3}{9.12}+...+\frac{3}{93.96}+\frac{3}{96.99}\)

\(A=1-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{93}-\frac{1}{96}+\frac{1}{96}-\frac{1}{99}\)

\(A=1-\frac{1}{99}=\frac{98}{99}\)

Vậy A=\(\frac{98}{99}\)

Answer 2

[나 재민]

\(B=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{95.98}\)

\(3B=\)\(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{95.98}\)

\(3B=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{95}-\frac{1}{98}\)

\(3B=\frac{1}{2}-\frac{1}{98}=\frac{24}{49}\)

\(B=\frac{24}{49}:3=\frac{8}{49}\)

Vậy B=\(\frac{8}{49}\)

Dấu "." là dấu nhân.

_Học tốt_