11+4+4+4=?
K
Khách
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1 tháng 5 2015
\(A=\frac{4}{3}\cdot\frac{4}{7}+\frac{4}{7}\cdot\frac{4}{11}+\frac{4}{11}\cdot\frac{4}{15}+...+\frac{4}{95}\cdot\frac{4}{99}\)
\(A=\frac{16}{3\cdot7}+\frac{16}{7\cdot11}+\frac{16}{11\cdot15}+...+\frac{16}{95\cdot99}\)
\(A=4\cdot\left(\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{95\cdot99}\right)\)
\(A=4\cdot\left(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{95}-\frac{1}{99}\right)\)
\(A=4\cdot\left(\frac{1}{3}-\frac{1}{99}\right)\)
\(A=4\cdot\frac{32}{99}\)
\(A=\frac{128}{99}\)
1 tháng 5 2015
\(A=\frac{4}{3}\times\frac{4}{7}+\frac{4}{7}\times\frac{4}{11}+...+\frac{4}{95}\times\frac{4}{99}\)
\(=4\times\frac{4}{3.7}+4\times\frac{4}{7.11}+...+4\times\frac{4}{95.99}\)
\(=4\times\left(\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+...+\frac{4}{95.99}\right)\)
\(=4\times\left(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{91}-\frac{1}{95}+\frac{1}{95}-\frac{1}{99}\right)\)
\(=4\times\left(\frac{1}{3}-\frac{1}{99}\right)\)
\(=4\times\frac{32}{99}\)
\(=\frac{128}{99}\)
BL
0
28 tháng 4 2022
7/11.3/4+7/11.1/4+4/11
=7/11.(3/4+1/4)+4/11
=7/11.1+4/11
=7/11+4/11
=1
20 tháng 7 2018
\(=\dfrac{-15}{4}.\dfrac{9}{11}+\dfrac{15}{4}.\dfrac{15}{11}-\dfrac{15}{4}.\dfrac{6}{11}\)
= \(\dfrac{15}{4}.\dfrac{-9}{11}+\dfrac{15}{4}.\dfrac{15}{11}-\dfrac{15}{4}.\dfrac{6}{11}\)
= \(\dfrac{15}{4}.\left(\dfrac{-9}{11}+\dfrac{15}{11}-\dfrac{6}{11}\right)\)
= \(\dfrac{15}{4}.\left(\dfrac{6}{11}-\dfrac{6}{11}\right)\)
= \(\dfrac{15}{4}.\left(\dfrac{0}{11}\right)\)
= \(\dfrac{15}{4}.0\)
= 0
NT
0
NT
1
9 tháng 4 2017
=-17/44:7/11+5/77:7/11
=(-1 7/44+5/77):7/11
=-9/28:7/11
=-99/196
29 tháng 5 2018
\(A=\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4\cdot7}+\frac{4}{7\cdot11}+...+\frac{10}{46\cdot56}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{46}-\frac{1}{56}\)
\(A=1-\frac{1}{56}\)
\(A=\frac{55}{56}\)
\(B=\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(B=\frac{1}{3}-\frac{1}{27}\)
\(B=\frac{8}{27}\)
\(C=\frac{4}{3\cdot6}+\frac{4}{6\cdot9}+\frac{4}{9\cdot12}+...+\frac{4}{99\cdot102}\)
\(C=\frac{4}{3}\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{99\cdot102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{99}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\cdot\frac{33}{102}\)
\(C=\frac{22}{51}\)
11 + 4 + 4 + 4 = 23
Đáp án :
11 + 4 + 4 + 4 = 23
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