\(\left(x-\frac{1}{2}\right)\cdot\frac{5}{2}+\frac{1}{2}=\frac{7}{4}\)
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Ta có \(\left(x-\frac{1}{2}\right).\frac{5}{2}+\frac{1}{2}=\frac{7}{4}\)
\(\Rightarrow\left(x-\frac{1}{2}\right).\frac{5}{2}=\frac{7}{4}-\frac{1}{2}\)
\(\Rightarrow\left(x-\frac{1}{2}\right).\frac{5}{2}=\frac{5}{4}\)
\(\Rightarrow x-\frac{1}{2}=\frac{5}{4}\div\frac{5}{2}\)
\(\Rightarrow x-\frac{1}{2}=\frac{1}{2}\)
\(\Rightarrow x=1\)
(x-\(\frac{1}{2}\)).\(\frac{5}{2}\)+\(\frac{1}{2}\)=\(\frac{7}{4}\)
(x-\(\frac{1}{2}\)).\(\frac{5}{2}\)=\(\frac{7}{4}\)- \(\frac{1}{2}\)
(x-\(\frac{1}{2}\)).\(\frac{5}{2}\)= \(\frac{7}{4}\)- \(\frac{2}{4}\)
(x-\(\frac{1}{2}\)).\(\frac{5}{2}\)\(\frac{5}{2}\)= \(\frac{5}{4}\)
(x-\(\frac{1}{2}\)) = \(\frac{5}{4}\): \(\frac{5}{2}\)= \(\frac{5}{4}\). \(\frac{2}{5}\)= \(\frac{1}{2}\)
x = \(\frac{1}{2}\)+ \(\frac{1}{2}\)=\(\frac{1}{4}\)
vậy x\(\frac{7}{4}\)\(\frac{7}{4}\)