Question

[kiss_rain_and_you]

cầu gì nhà nào cũng có?

Answer 1

[s2 Lắc Lư s2]

\(x+y\ge\sqrt[3]{xy}\left(\sqrt[3]{x}+\sqrt[3]{y}\right)\Rightarrow x+y+1\ge\sqrt[3]{xy}\left(\sqrt[3]{x}+\sqrt[3]{y}+\sqrt[3]{z}\right)\)

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