Tìm x:
13x-2/2x+5 = -27/5-x
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\(\frac{2x-10}{6}=\frac{-27}{5-x}\)
\(\frac{2\left(x-5\right)}{6}=\frac{27}{x-5}\)
\(2\left(x-5\right)^2=27\times6\)
\(2x^2-20x+50-162=0\)
\(2x^2-20x-112=0\)
\(x^2-10x-56=0\)
\(x^2-14x+4x-56=0\)
\(\left(x-14\right)\left(x+4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-14=0\\x+4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=14\\x=-4\end{cases}}\)
KL .....
XIN TIICK
|x - 5| = |-7|
=> |x - 5| = 7
=> \(\orbr{\begin{cases}x-5=7\\x-5=-7\end{cases}}\)
=> \(\orbr{\begin{cases}x=12\\x=-2\end{cases}}\)
c ) | x - 5 | = | -7 |
cs 2 trường hợp
TH1 x-5=7
x=5+7
x=12
TH2 x-5=-7
x=-7+5
x=-2
# chi kute@#
Đề trước đó:
(x-7)(x+1)-(x-3)^2=(3x-5)(3x+5)-(3x+1)^2+(x-2)^2-x
<=>x^2+x-7x-7-x^2+6x-9=9x^2-25-9x^2-6x-1+x^2-4x+4-x
<=>x^2-11x-6=0
<=>x^2-2x. 11/2 + 121/4-145/4=0
<=>(x-11/2)^2=145/4
<=>|x-11/2|=căn(145)/2
<=>x=[11+-căn(145)]/2
a) (426 + x) : 5 = 120
(=) 426 + x = 120 :5
(=) 426 + x = 24
(=) x = 24 - 426
(=) x = - 402
Vậy x = - 402
b) 5844 : x -159 = 328
(=) 5844 : x = 328+ 159
(=) 5844 : x = 487
(=) x = 5844 : 487
(=) x = 12
Vậy x = 12
c) 32x + 1 = 27
(=) 32x = 27 -1
(=) 32x = 26
=> vô lý
vậy x thuộc tập hợp rỗng
d) (3x - 1)2 = 64
(=) (3x - 1)2 = 82
(=) 3x - 1 = 8
(=) 3x = 8 + 1
(=) 3x = 9
(=) x = 9 : 3
(=) x = 3
Vậy x = 3
( 426 + x ) : 5 = 120
( 426 + x ) = 600
x = 600 - 426
x = 174
b ) 5844 : x - 159 = 328
5844 : x = 328 + 159
5844 : x = 487
x = 5844 : 487
x = 12
d ) ( 3x - 1 ) 2 = 64
( 3x - 1 ) = 8
3x = 9
x = 3
Ta có :\(\hept{\begin{cases}-2x-11:3x+2\\3x+2:3x+2\end{cases}}\)\(\implies\)\(\hept{\begin{cases}3.\left(-2x-11\right):3x+2\\2\left(3x+2\right):3x+2\end{cases}}\) \(\implies\) \(\hept{\begin{cases}-6x-33:3x+2\\6x+4:3x+2\end{cases}}\)
\(\implies\) \(-6x-33+6x+4:3x+2\)
\(\implies\) \(-29:3x+2\)
\(\implies\) \(3x+2\) \(\in\) Ư(-29)=\(\{\)\(1;-1;29;-29\) \(\}\)
\(\implies\) \(x\) \(\in\) \(\{\) \(-1;9\)\(\}\)
\(\Leftrightarrow\left\{{}\begin{matrix}8x-20y=44\\15x+20y=25\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=-1\end{matrix}\right.\)
a) \(\left(x-\frac{1}{2}\right)^4=\frac{1}{81}\)
\(\Rightarrow\left(x-\frac{1}{2}\right)^4=\left(\frac{1}{3}\right)^4\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{2}=\frac{1}{3}\\x-\frac{1}{2}=\frac{-1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{5}{6}\\x=\frac{1}{6}\end{cases}}\)
Vậy ...
\(\frac{13x-2}{2x+5}=-\frac{27}{5-x}\)ĐK : \(x\ne-\frac{5}{2};5\)
\(\Rightarrow\left(13x-2\right)\left(5-x\right)=-27\left(2x+5\right)\)
\(\Leftrightarrow65x-13x^2-10+2x=-54x-135\)
\(\Leftrightarrow-13x^2+121x+125=0\Leftrightarrow x=10,24...;x=-0,93...\)