130ta= tan
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28 cm = 280 mm 3000 cm = 30 m
312 m = 3120 dm 4500 m = 45 hm
105 dm = 1050 cm 165 dm = 16 m 5 dm
7 m 25 cm = 725 cm 2080 m = 2 km 80 m
2 km 5 kg = .......? ( đề bài sai ) 730 cm = 0,73 dam
15 km = 15000 m 18000 m = 18 km
21 yến = 210 kg 320 kg = 32 yến
130 tạ = 13000 kg 4600 kg = 46 tạ
44 tấn = 44000 kg 19000 kg = 19 tấn
3 kg 125 g = 3125 g 1256 g = 1 kg 256 g
2 kg 50 g = 2050 g 6005 g = 6 kg 5 g
8 dam2 = 800 m2 300 m2 = 3 dam2
20 hm2 = 2000 dam2 2100 dam2 = 21 hm2
5 cm2 = 500 mm2 900 mm2 = 9 cm2
28cm = 2800mm 3000cm = 30m
312m = 3120dm 4500m = 45hm
105dm = 1050cm 165dam = 1650m = 16500dm
7m25cm = 725cm 2080m = 2,08km=2080m
2km50g = ...m ( sai đề) 730cm = 0,73dam
15km = 15000m 18000m = 18km
21yen = 210kg 320kg = 32yen
130ta = 13000kg 4600k = ... ta ( đề sai )
44tan = 44000kg 19000kg = 19tan
3kg125g = 3125g 1256g = 1,256kg=1256g
2kg50g = 2050g 6005g=6,005kg=6005g
8dam2= 800m2 300m2 = 3dam2
20hm2 = 2000dam2 2100dam2 = 21 hm2
5cm2 = 50mm2 900mm2 = 9cm2
gợi ý tan 10o = cot 80o
mà tan a . cot a =1
phần còn lại tự làm
chưa hiểu thì hỏi nhé
\(A+B+C=180^0\Rightarrow tan\left(A+B\right)=-tanC\)
\(\Rightarrow\frac{tanA+tanB}{1-tanA.tanB}=-tanC\Leftrightarrow tanA+tanB=-tanC+tanA.tanB.tanC\)
\(\Leftrightarrow tanA+tanB+tanC=tanA.tanB.tanC\)
\(2A+2B+2C=360^0\Rightarrow tan\left(2A+2B\right)=-tan2C\)
\(\Leftrightarrow\frac{tan2A+tan2B}{1-tan2A.tan2B}=-tan2C\)
\(\Leftrightarrow tan2A+tan2B+tan2C=tan2A.tan2B.tan2C\)
\(A+B+C=\pi\Rightarrow\dfrac{A}{2}+\dfrac{B}{2}=\dfrac{\pi}{2}-\dfrac{C}{2}\)
\(\Rightarrow tan\left(\dfrac{A}{2}+\dfrac{B}{2}\right)=tan\left(\dfrac{\pi}{2}-\dfrac{C}{2}\right)\)
\(\Rightarrow\dfrac{tan\dfrac{A}{2}+tan\dfrac{B}{2}}{1-tan\dfrac{A}{2}tan\dfrac{B}{2}}=cot\dfrac{C}{2}=\dfrac{1}{tan\dfrac{C}{2}}\)
\(\Rightarrow\left(tan\dfrac{A}{2}+tan\dfrac{B}{2}\right)tan\dfrac{C}{2}=1-tan\dfrac{A}{2}tan\dfrac{B}{2}\)
\(\Rightarrow tan\dfrac{A}{2}tan\dfrac{B}{2}+tan\dfrac{B}{2}tan\dfrac{C}{2}+tan\dfrac{C}{2}tan\dfrac{A}{2}=1\)
ta có: A\2+B\2 = π\2 - C\2
⇒ tan(A\2+B\2) = tan(π\2 -C\2)
⇒ (tanA\2 +tanB\2)\[1 - tanA\2.tanB\2] = cotgC\2
⇒ (tanA\2 +tanB\2).tanC\2 = [1 - tanA\2.tanB\2]
⇒ tanA\2.tanB\2 + tanB\2.tanC\2 + tanC\2.tanA\2 = 1
............đpcm............
a/ \(tan3x=tanx\Rightarrow3x=x+k\pi\Rightarrow2x=k\pi\Rightarrow x=\frac{k\pi}{2}\)
b/ \(tan3x+tanx=0\Rightarrow tan3x=-tanx=tan\left(\pi-x\right)\)
\(\Rightarrow3x=\pi-x+k\pi\Rightarrow4x=\pi+k\pi\Rightarrow x=\frac{\pi}{4}+\frac{k\pi}{4}\)
c/ \(tan2x-tanx=0\Rightarrow tan2x=tanx\)
\(\Rightarrow2x=x+k\pi\Rightarrow x=k\pi\)
d/ \(tan2x+tanx=0\Rightarrow tan2x=-tanx=tan\left(\pi-x\right)\)
\(\Rightarrow2x=\pi-x+k\pi\Rightarrow3x=\pi+k\pi\Rightarrow x=\frac{\pi}{3}+\frac{k\pi}{3}\)
\(tan10^0.tan80^0.tan20^0.tan70^0.tan30.tan60.tan40.tan50\)
\(=tan10.tan\left(90-10\right).tan20.tan\left(90-20\right).tan30.tan\left(90-30\right).tan40.tan\left(90-40\right)\)
\(=tan10.cot10.tan20.cot20.tan30.cot30.tan40.cot40\)
\(=1.1.1.1=1\)
Tối sẽ không bao giờ tha thứ cho OLM
130ta= 13 tấn
(nháy đúng nha thanks)