\(\frac{2^7.9^3}{6^5.8^2}=.....=........=......=....=.....\)
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\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}\)
\(=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)
\(\frac{2^7.9^3}{6^5.8^2}\)
\(=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{3}{2^4}=\frac{3}{16}\)
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\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\)\(\frac{3}{16}\)
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(3.2\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{3^5.2^5.2^6}=\frac{2^7.3^5.3}{3^5.2^{11}}=\frac{2^7.3}{2^7.2^4}=\frac{3}{2^4}=\frac{3}{16}\)
Bài này cx là BTVN của mk, mk làm giống vậy đấy
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3.3\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^3.3^3}{2^5.3^5.2^6}=\frac{3}{16}\)
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.3^6}{3^5.2^5.2^6}=\frac{2^7.3^6}{3^5.2^{11}}=\frac{3}{2^4}=\frac{3}{16}\)
a) \(=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)
b) \(=-\frac{3^3.2^3+3.3^2.2^2+3^3}{13}=-\frac{3^3.2^3+3^3.2^2+3^3}{13}=-\frac{3^3.\left(2^3+2^2+1\right)}{13}=-\frac{3^3.13}{13}=-3^3=-27\)
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{3^5.2^{11}}=\frac{2^7.3^5.3}{3^5.2^7.2^4}=\frac{3}{2^4}=\frac{3}{16}\)