( -1/2 )^2 : ( -1/4 ) - 2 . ( -1/2 )^3 + ( 25 - 23 )^2 =
25^10 . (1/5)^20 + ( -3/4 )^8 . ( -4/3)^8 - 2016^0
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1: \(=\dfrac{1}{4}:\dfrac{-1}{4}-2\cdot\dfrac{-1}{8}+5-4\)
\(=-1+1+\dfrac{1}{4}=\dfrac{1}{4}\)
2: \(=5^{20}\cdot\dfrac{1}{5^{20}}+\left(\dfrac{3}{8}\cdot\dfrac{4}{3}\right)^8-1=1-1+\dfrac{1}{2}^8=\dfrac{1}{2^8}\)
80 - 4 . 52 + 3 .23=80 - 4 . 25 + 3 . 8=80 - 100 +24=-20+24=4
25 . 124 - 24 . 25 +212=24 .(124 - 25)+212=24 . 99 +212=2376 +212=2588
35 . 48 + 65 . 68 + 20 . 35=35 . (48 +20)+65 . 68=35 . 68 +65 . 68=68 . (35 + 65)=68 . 100=6800
27 :23+23.20-110=24+23- 1=16 + 8 -1=23
câu 3,câu 6,câu 7 mk ko làm đc vì ko biết cách viết dấu móc vuông với dấu móc kép nha bạn.:) ^_^
HOK TỐT
a, \(\left(4\dfrac{1}{9}+3\dfrac{1}{4}\right).2\dfrac{1}{4}+2\dfrac{3}{4}\)
\(=\left(\dfrac{37}{9}+\dfrac{13}{4}\right).\dfrac{9}{4}+\dfrac{11}{4}\)
\(=\dfrac{265}{36}.\dfrac{9}{4}+\dfrac{11}{4}\)
\(=\dfrac{265}{16}+\dfrac{11}{4}\)
\(=\dfrac{309}{16}\)
b, \(\dfrac{9}{23}.\dfrac{5}{8}+\dfrac{9}{23}.\dfrac{3}{8}-\dfrac{9}{23}\)
\(=\dfrac{45}{184}+\dfrac{27}{184}-\dfrac{9}{23}\)
\(=\dfrac{9}{23}-\dfrac{9}{23}\)
\(=\dfrac{1}{1}\)
c, \(1+\left(\dfrac{9}{10}-\dfrac{4}{5}\right)\div3\dfrac{1}{6}\)
\(=1+\left(\dfrac{9}{10}-\dfrac{4}{5}\right)\div\dfrac{19}{6}\)
\(=1+\dfrac{1}{10}\div\dfrac{19}{6}\)
\(=1+\dfrac{3}{95}\)
\(=1\dfrac{3}{95}\)
d, ???
1, Tìm x :
a, \(x^7.x^5=3^{12}\)
\(\Rightarrow x^{12}=3^{12}\)
\(\Rightarrow x=3\)
Vậy x = 3
b, \(\left(x+1\right)^4=5^8\div25^4\)
\(\left(x+1\right)^4=5^8\div\left(5^2\right)^4\)
\(\left(x+1\right)^4=5^8\div5^8\)
\(\left(x+1\right)^4=1\)
\(\Rightarrow x\in\left\{0;1\right\}\)
Vậy \(x\in\left\{0;1\right\}\)
c, \(x^6=x\)
\(\Rightarrow x^6-x=0\)
\(\Rightarrow x.x^5-x.1=0\)
\(\Rightarrow x\left(x^5-1\right)=0\)
x = 0 hoặc x5 - 1 = 0
x = 0 hoặc x5= 1
x = 0 hoặc x5 = 1
\(\Rightarrow x\in\left\{0;1\right\}\)
Vậy \(x\in\left\{0;1\right\}\)
2, Tính :
\(\left(4^{20}+4^{15}\right)\div\left(4^{10}+4^5\right)\)
\(=4^{15}.\left(4^5+1\right)\div4^5.\left(4^5+1\right)\)
\(=4^{15}\div4^5\)
\(=4^{10}\)
Vậy giá trị biểu thức trên bằng 410
\(A=2^0+2^1+2^2+...+2^{2016}\)
\(2A=2+2^2+2^3+...+2^{2017}\)
\(2A-A=\left(2+2^2+2^3+...+2^{2017}\right)-\left(2^0+2^1+2^2+...+2^{2016}\right)\)
\(\Rightarrow A=2^{2017}-1\)
Vậy : \(A=2^{2017}-1\)
BÀI 1: Tính
1) -(-10)-(+14)=10-14=-4
2) -(+15)-12=-15-12=-27
3) (-11)-(-13)=-11+13=2
4) -(-13)-(-10)=13+10=23
5) -4-(+7)=-4-7=-11
Bài 2 : tìm x:
a)x+(-5)=-(-7)
x=7+(-5)
x=2
vậy x=2
b)x-8=-(+10)
x-8=10
x=10+8
x=18
vậy x=18
c)x-(-12)=14
x+12=14
x=14-12
x=2
vậy x=2
d)x-(+3)=-17
x-3=17
x=17+3
x=20
vậy x=20
e)x+20=-(-23)
x+20=23
x=23-20
x=3
vậy x=3
BÀI 3:tính
a)17-(-9)-(+25)
=17+9-25
=26-25
=1
b)-[-13]-15+(-20)
=13-15-20
=-2-20
=-22
c)-17-(-16)-23
=-17+16-23
=-1-23
=-24
d)-(-25)-(-14)+(-17)
=25+14-17
=39-17
=22
cảm ơn bạn rất nhiều chúc bạn và gia đình mạnh khỏe, vui vẻ bên nhau và cùng đón 1 cái TẾT vui vẻ!
HAPPY NEW YEAR
b)1/2*2/3*3/4*4/5*5/6*6/7*7/8*8/9*9/10
=1x2x3x4x5x6x7x8x9
2x3x4x5x6x7x8x9x10
= 1
10
\(\left(-\frac{1}{2}\right)^2\div\left(-\frac{1}{4}\right)-2\times\left(-\frac{1}{2}\right)^3+\left(25-23\right)^2\)
\(=\frac{1}{4}\div\left(-\frac{1}{4}\right)-2\times\left(-\frac{1}{8}\right)+2^2\)
\(=-1+\frac{1}{4}+4\)
\(=\frac{13}{4}\)
*****
\(25^{10}\times\left(\frac{1}{5}\right)^{20}+\left(-\frac{3}{4}\right)^8\times\left(-\frac{4}{3}\right)^8-2016^0\)
\(=25^{10}\times\left[\left(\frac{1}{5}\right)^2\right]^{10}+\left[\left(-\frac{3}{4}\right)\times\left(-\frac{4}{3}\right)\right]^8\)
\(=25^{10}\times\left(\frac{1}{25}\right)^{10}+1^8-0\)
\(=\left(25\times\frac{1}{25}\right)^{10}+1\)
\(=1^{10}+1\)
= 1 + 1
= 2
2 câu khác nhau đấy nhé!