tính bằng hai cách
2/5x3/7+2/5x4/7
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\(\frac{3}{5}\times\frac{3}{7}\times\frac{2}{5}\times\frac{4}{7}\)
\(=\frac{9}{35}\times\frac{8}{35}=\frac{72}{1225}\)
C2 : \(\frac{3}{5}\times\frac{3}{7}\times\frac{2}{5}\times\frac{4}{7}=\frac{72}{1225}\)
k cho mik nha
Cách 1
\(\frac{2}{5}\times\frac{3}{7}\times\frac{2}{5}\times\frac{4}{7}\)
\(=\frac{6}{35}\times\frac{2}{5}\times\frac{4}{7}\)
\(=\frac{12}{175}\times\frac{4}{7}\)
\(=\frac{48}{1225}\)
Đúng 100%
Tk mk mk tk lại
Cảm ơn bạn nhiều
Thank you very much
( ^ _ ^ )
a) C1:
= 11/10 x 4/5 = 44/50 = 22/25
C2:
= 3/5 x 4/5 + 1/2 x 4/5 = 12/25 + 2/5 = 22/25
b) C1:
= 2/5 x (3/7 + 4/7) = 2/5 x 1 = 2/5
C2:
= 6/35 + 8/35 = 14/35 = 2/5
a)(3/5+1/2)x4/5
= \(\left(\dfrac{6}{10}+\dfrac{5}{10}\right)\times\dfrac{4}{5}=\dfrac{11}{10}\times\dfrac{4}{5}=\dfrac{22}{25}\)
\(=\dfrac{3}{5}\times\dfrac{4}{5}+\dfrac{1}{2}\times\dfrac{4}{5}=\dfrac{12}{25}+\dfrac{2}{5}=\dfrac{22}{25}\)
b)2/5x3/7+2/5x4/7
\(=\dfrac{6}{35}+\dfrac{8}{35}=\dfrac{14}{35}=\dfrac{2}{5}\)
\(=\dfrac{2}{5}\times\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\dfrac{2}{5}\times1=\dfrac{2}{5}\)
\(\)
a) C1 : 2/5 x 3/7 + 2/7 x 4/7
= 2/5 x (3/7 + 4/7)
= 2/5 x 1
= 2/5
C2 : 2/5 x 3/7 + 2/5 x 4/7
= 6/35 + 8/35
= 2/5
b) (2/3 - 4/7) x 5/5
= 2/21 x 5/5
= 2/21
C2 : (2/3 - 4/7) x 5/5
= 2/3 x 1 - 4/7 x 1
= 2/3 - 4/7
= 2/21
c) 3/4 x 2/5 - 3/4 x 2/7
= 3/4 x (2/5 - 2/7)
= 3/4 x 4/35
= 3/35
C2 : 3/4 x 2/5 - 3/4 x 2/7
= 3/10 - 3/14
= 3/35
a,
Cách 1
\(\frac{2}{5}\times\frac{3}{7}+\frac{2}{5}\times\frac{4}{7}\)
\(=\frac{6}{35}+\frac{8}{35}\)
\(=\frac{2}{5}\)
Cách 2 :
\(\frac{2}{5}\times\frac{3}{7}+\frac{2}{5}\times\frac{4}{7}\)
\(=\frac{2}{5}\times\left(\frac{3}{7}+\frac{4}{7}\right)\)
\(=\frac{2}{5}\times1\)
\(=\frac{2}{5}\)
b,
Cách 1 :
\(\left(\frac{2}{3}-\frac{4}{7}\right)\times\frac{5}{5}\)
\(=\frac{2}{21}\times1\)
\(=\frac{2}{21}\)
Cách 2 :
\(\left(\frac{2}{3}-\frac{4}{7}\right)\times\frac{5}{5}\)
\(=\frac{2}{3}\times\frac{5}{5}-\frac{4}{7}\times\frac{5}{5}\)
\(=\frac{2}{3}-\frac{4}{7}\)
\(=\frac{2}{21}\)
c,
Cách 1 :
\(\frac{3}{4}\times\frac{2}{5}-\frac{3}{4}\times\frac{2}{7}\)
\(=\frac{3}{10}-\frac{3}{14}\)
\(=\frac{3}{35}\)
Cách 2 :
\(\frac{3}{4}\times\frac{2}{5}-\frac{3}{4}\times\frac{2}{7}\)
\(=\frac{3}{4}\times\left(\frac{2}{5}-\frac{2}{7}\right)\)
\(=\frac{3}{4}\times\frac{4}{35}\)
\(=\frac{3}{35}\)
Mk nhanh nhất đó
Đúng 100%
Tk mk mk tk lại
Cảm ơn bạn nhiều
Thank you very much
( ^ _ ^ )
a)
A(x) = \(x^6-2x^5+9x^4+5x^3-4x+7\)
B(x) = \(-x^6-2x^5+9x^4-5x^3+2x-7\)
b)
A(x)+B(x) = \(-4x^5+18x^4-2x\)
A(x)-B(x) = \(2x^6+10x^3-6x+14\)
1,
a, \(x\)x 124= 4829-365
\(x\)x 124 = 4464
\(x\)= 4464 :124
\(x\)= 36.
b,\(x\)x 137 = 25 x 3
\(x\)x 137 = 75
\(x\)= \(\frac{75}{137}\)
2,
\(\frac{4}{5}\)x\(\frac{3}{7}+\frac{4}{5}\)x\(\frac{6}{7}-\frac{4}{5}\)x\(\frac{4}{10}\)
=\(\frac{4}{5}\)x\(\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)=\(\frac{4}{5}\)x\(\frac{31}{35}\)\(\frac{124}{175}\)
\(\text{Bài }1\text{ : Tìm }x\text{ : }\)
\(a,\text{ }x\text{ x }124=4829-365\)
\(x\text{ x }124=4464\)
\(x=4464\text{ : }124\)
\(x=36\)
\(b,\text{ }x\text{ x }137=25\text{ x }3\)
\(x\text{ x }137=75\)
\(x=75\text{ : }137\)
\(x=\frac{75}{137}\)
\(\text{Bài }2\text{ : Tính bằng cách thuận tiện nhất : }\)
\(\frac{4}{5}\text{ x }\frac{3}{7}+\frac{4}{5}\text{ x }\frac{6}{7}-\frac{4}{5}\text{ x }\frac{4}{10}\)
\(=\frac{4}{5}\text{ x }\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)
\(=\frac{4}{5}\text{ x }\left(\frac{9}{7}-\frac{4}{10}\right)\)
\(=\frac{4}{5}\text{ x }\frac{31}{35}\)
\(=\frac{124}{175}\)
x=4
=>x+1=5
A=(x+1)x^5 -(x+1)x^4+(x+1)x^3-(x+1)x^2+(x+1)x-1
=x^6+x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2-x+1
=x^6-x-1
=4^6-4-1
=4091
\(a,A=5\cdot4^5-5\cdot4^4+5\cdot4^3-5\cdot4^2+5\cdot4+1\\ A=4^4\left(20-5\right)+4^2\left(20-5\right)+\left(20-5\right)\\ A=15\left(4^4+4^2+1\right)=15\cdot273=4095\)
\(b,x=7\Leftrightarrow x+1=8\\ \Leftrightarrow B=x^{2006}-\left(x+1\right)x^{2005}+\left(x+1\right)x^{2004}-...+\left(x+1\right)x^2-\left(x+1\right)x-5\\ B=x^{2006}-x^{2006}-x^{2005}+x^{2005}+x^{2004}-...+x^3+x^2-x^2-x-5\\ B=-x-5=-12\)
a.Mik làm rồi nhé!
\(b.P\left(x\right)+Q\left(x\right)=\left(2x^2-x+5\right)+\left(-2x^2+4x-1\right)\\ =2x^2-x+5-2x^2+4x-1\\ =3x+4\\ ------\\ P\left(x\right)-Q\left(x\right)=\left(2x^2-x+5\right)-\left(-2x^2+4x-1\right)\\ =2x^2-x+5+2x^2-4x+1\\ =4x^2-5x+6\)
\(c.\)nghiệm của đa thức P(x) + Q(x)
\(3x+4=0\\ \Leftrightarrow3x=-4\\ \Leftrightarrow x=\dfrac{-4}{3}\)
\(\Leftrightarrow\)vậy...
a, 5 x 4 + 9 x 5 - 5 x 3 - 10
= 5 x ( 4 + 9 - 3) - 10
= 5 x ( 13 - 3) - 10
= 5 x 10 - 10
= 40
b, 4 x 7 + 4 x 6 - 4 x 3 - 4
= 4 x 7 + 4 x 6 - 4 x 3 - 4 x1
= 4 x ( 7 + 6 - 3 -1)
= 4 x 9
= 36
Cách 1:
\(\frac{2}{5}\) \(.\) \(\frac{3}{7}\) \(+\) \(\frac{2}{5}\) \(.\) \(\frac{4}{7}\)
= \(\frac{6}{35}\) \(+\) \(\frac{8}{35}\)
= \(\frac{2}{5}\)
Cách 2:
\(\frac{2}{5}\) \(.\) \(\frac{3}{7}\) \(+\) \(\frac{2}{5}\) \(.\) \(\frac{4}{7}\)
= \(\frac{2}{5}\) \(.\) ( \(\frac{3}{7}\) \(+\) \(\frac{4}{7}\) )
= \(\frac{2}{5}\) \(.\) \(1\)
= \(\frac{2}{5}\)
\(-\) \(Hok\) \(T\) \(-\)
\(C1:\frac{2}{5}\cdot\frac{3}{7}+\frac{2}{5}\cdot\frac{4}{7}=\frac{6}{35}+\frac{8}{35}=\frac{2}{5}\)