Cho x=2015
Tính A = x2015 -2014x2014 -2014x2013 - ... - 2014x2 - 2014x + 1
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x = 2013 => x + 1 = 2014
Ta có:\(B=x^{2013}-2014x^{2012}+2014x^{2011}-2014x^{2010}+...+2014x-1\)
\(=x^{2013}-\left(x+1\right)x^{2012}+\left(x+1\right)x^{2011}-\left(x+1\right)x^{2010}+...+\left(x+1\right)x-1\)
\(=x^{2013}-x^{2013}-x^{2012}+x^{2012}+x^{2011}-x^{2011}-x^{2010}+...+x^2+x-1\)
\(=x-1\)
\(=2013-1\)
\(=2012\)
\(X=2013\Rightarrow2014=X+1\Rightarrow B=X^{2013}-\left(X+1\right)\times X^{2012}+...+\left(X+1\right)\times X-1\)\(X-1\)
\(\Rightarrow B=X^{2013}-X^{2013}-X^{2012}+...+X^2+X-1\)
\(\Rightarrow B=X-1\)\(=2013-1=2012\)
cho 2014=2013+1 thay vào ta có:\(B=x^{2013}-\left(2013+1\right)x^{2012}+\left(2013+1\right)x^{2011}-...-\left(2013+1\right)x^2+\left(2013+1\right)x-1\)
\(=x^{2013}-\left(x+1\right)x^{2012}+\left(x+1\right)x^{2011}-...-\left(x+1\right)x^2+\left(x+1\right)x-1\)
\(=x^{2013}-x^{2013}-x^{2012}+x^{2012}+x^{2011}-...-x^3-x^2+x^2+x-1\)
\(=x-1=2013-1=2012\)
=(1+2+3+4+5+6+7+.....+108+109)x(2014x(3-2-1))
=(1+2+3+4+5+6+7+.....+108+109)x(2014x0)
=Ax0
=0
A= x2015 - 2014x2014 - 2014x2013 - ...- 2014x2 - 2014x + 1
= x2015 - (2015-1)x2014 - (2015-1)x2013 -...- (2015-1)x2 - (2015-1)x + 1
= x2015 - 2015x2014+1 - 2015x2013+1 -...- 2015x2+1 - 2015x+1+1
= x2015 - 2015x2014 - 2015x2013 -...- 2015x2 - 2015x+ (1+1+1+...+1)
Thay x= 2015 vào biểu thức ta có:
=20152015 - 20152015 - 20152014-...- 20153 - 20152+2015
=0 - 2.20152014 -...- 2.20153 - 20152 + 2015
= -2.( 20152014 - ...- 20153) - 20152+2015