Tìm X: nhé
a.( X- ) x b. 4,25 x ( X + 41,53) – 125 = 53,5
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\(4,25\times\left(x+41,53\right)-125=53,5\)
\(4,25\times\left(x+41,53\right)=53,5+125\)
\(4,25\times\left(x+41,53\right)=178,5\)
\(x+41,53=178,5:4,25\)
\(x+41,53=42\)
\(x=42-41,53\)
\(x=0,47\)
a) 53,2 : ( x -3,5 ) + 45,8 =99
<=>53,2 : ( x -3,5 ) = 99 - 45,8
<=> 53,2 : ( x -3,5 ) = 53,2
<=> x - 3,5 = 53,2 : 53,2
<=> x -3,5 = 1
<=> x = 1 + 3,5
<=> x = 4,5
Vậy x =4,5
b) 4,25 . ( x + 41,53 ) - 125 = 53,5
<=> 4,25 .( x + 41,53 ) = 53,5 + 125
<=> 4,25 .( x + 41,53 ) = 178,5
<=> x + 41,53 = 178 : 4,25
<=> x + 41,53 = 42
<=> x = 42 - 41,53
<=> x = 0,47
Vậy x =0,47
a) \(53,2:\left(x-3,5\right)+45,8=99\)
\(\Leftrightarrow53,2:\left(x-3,5\right)=53,2\)
\(\Leftrightarrow x-3,5=1\)
\(\Leftrightarrow x=4,5\)
b) \(4,25\times\left(x+41,53\right)-125=53,5\)
\(\Leftrightarrow4,25\times\left(x+41,53\right)=178,5\)
\(\Leftrightarrow x+41,53=42\)
\(\Leftrightarrow x=0,47\)
\(\text{53,2:[x-3,5]+45,8=99}\)
\(\text{53,2:[x-3,5] =99-45,8}\)
\(\text{53,2:[x-3,5] =53,2}\)
\(\text{ x-3,5 =53,2:53,2}\)
\(\text{ x-3,5 =1}\)
\(\text{ x =4,5}\)
\(\text{4,25x[x+41,53]-125=53,5}\)
\(\text{4,25x[x+41,53] =53,5+125}\)
\(\text{4,25x[x+41,53] =178,5}\)
\(\text{ x+41,53 =178,5:4,25}\)
\(\text{ x+41,53 =42}\)
\(\text{ x =42+41,53}\)
\(\text{ x =83,53}\)
\(53,2\div\left(x-3,5\right)+45,8=99\)
\(53,2\div\left(x-35\right)=99-45,8\)
\(53,2\div\left(x-35\right)=53,2\)
\(x-35=1\)
\(x=1+35\)
\(x=36\)
\(4,25\times\left(x+41,53\right)-125=53,5\)
\(4,25\times\left(x+41,53\right)=53,5+125\)
\(4,25\times\left(x+41,53\right)=178,5\)
\(x+41,53=178,5\div4,25\)
\(x+41,53=42\)
\(x=42-41,53\)
\(x=0,47\)
53,2:[x-3,5]+45,8=99
53,2:[x-3,5] =99-45,8
53,2:[x-3,5] =53,2
x-3,5 =53,2:53,2
x-3,5 =1
x =1+3,5
x =4,5
53,2:(x-3,5)+45,8=99
53,2:(x-3,5) =99-45,8
53,2:(x-3,5) =53,2
x-3,5 =53,2:53,2
x-3,5 =1
x =1+3,5
x =4,5
71+65x4=x+260
331 =x+260
x =331-260
x =71
4,25x(x+41,53)-125=53,5
4,25x(x+41,53) =53,5+125
4,25x(x+41,53) =178,5
x+41,53 =178,5:4,25
x+41,53 =42
x =42-41,53
x =0,47
A ,53,2 : ( x - 3,5 ) + 45,8 = 99
53,2 : ( x - 3,5 ) = 99 - 45,8
53,2 : ( x - 3,5 ) = 53,2
x - 3,5 = 53,2 : 53,2
x - 3,5 = 1
x = 1 + 3,5
x = 4,5
Vậy x = 4,5
B , 71 + 65 x 4 = x + 260
= 71 + 260 = x + 260
= 331 = x + 260
= 331 - 260
= 71
Vậy x = 71
C , 4,25 x ( x + 41,53 ) - 125 = 53,5
= 4,25 x ( x + 41,53 ) = 53,5 + 125
= 4,25 × ( x + 41,53 ) = 178,5
= x + 41,53 = 178,5 : 4,25
= x + 41,53 = 42
= x = 42 - 41,53
x = 0,47
Vậy x = 0,47
# học tốt , nhớ k #
4,25 x (X+41,53)-125=53,5
4,25 x (X+41,53)=53,5+125
4,25x(X+41,53)=178,5
X+41,53=178,5:4,25
X+41,53=42
X=42-41,53
X=0,47
vậy...........
53,2 : (x - 3,5 ) + 45,8 = 99
53,2 : (x - 3,5 ) = 99-45,8
53,2 : (x - 3,5 ) = 53,2
x-3,5=53,2:53,2
x-3,5=1
x=1+3,5
x=4,5
4,25 x ( X + 41,53 ) - 125 = 53,5
4,25 x ( X + 41,53 ) =53,5+125
4,25 x ( X + 41,53 ) =178,5
X + 41,53=178,5:4,25
X + 41,53=42
X=42-41,53
X=0,47
a) Thay a = 58,47 ta được:
\(A=4,25\times\left(58,47+41,53\right)-125=4,25\times100-125=425-125=300\)
B) Để A = 53,5 thì \(4,25\times\left(a+41,53\right)-125=53,5\)
=> 4,25 x (a+41,53) = 178,5
=> a + 41,53 = 42
=> a = 42 - 41,53
=> a = 0,47
Vậy khi a - 0,47 thì A = 53,5
a, Thay a = 58,47 vào biểu thức A ta được :
A = 4,25 x (58,47 + 41,53) - 125
A = 4,25 x 100 - 125
A = 425 - 125
A = 300
b, Ta có : \(4,25\times\left(a+41,53\right)-125=53,5\)
=> 4,25 x (a + 41,53) = 53,5 + 125
=> 4,25 x (a + 41,53) = 178,5
=> a + 41,53 = 178,5 : 4,25
=> a + 41,53 = 42
=> a = 42 - 41,53
=> a = 0,47
Vậy a = 0,47