tìm x:
x(x+1)-2=(x-2).(x-3)
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\(\Leftrightarrow x^3+2x^2-3x-x^3-3x^2=-4\)
\(\Leftrightarrow x^2+3x-4=0\)
=>(x+4)(x-1)=0
=>x=-4 hoặc x=1
1) \(x:\dfrac{1}{3}=\dfrac{1}{2}+\dfrac{1}{3}\)
\(\Rightarrow3\times x=\dfrac{5}{6}\Rightarrow x=\dfrac{5}{18}\)
2) \(\left(x:\dfrac{2}{3}\right):\dfrac{2}{5}=\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{2}\times x=\dfrac{7}{10}\times\dfrac{2}{5}=\dfrac{7}{25}\)
\(\Rightarrow x=\dfrac{7}{25}:\dfrac{3}{2}=\dfrac{14}{75}\)
x * 2 + x * 3 + x * 4 + x = 2130
x * (2 + 3 + 4 + 1) = 2130
x * 10 = 2130
x = 2130 : 10 = 213
\(\Leftrightarrow x-\left[3-x+3+x-2\right]=0\)
=>x=4
x^2+x-2=x^2-3x-2x+6
x^2+x=x^2-3x-2x+8
x=x^2-3x-2x+8-x^2
x=-3x-2x+8
x=-5x+8
6x=8
=> x=8/6
6x=8
\(x\left(x+1\right)-2=\left(x-2\right).\left(x-3\right)\)
\(x^2+x-2=x.\left(x-3\right)-2.\left(x-3\right)\)
\(x^2+x-2=x^2-3x-2x+6\)
\(x^2+x-2=x^2-5x+6\)
\(\Rightarrow x^2+x-x^2+5x=6+2\)
\(x^2-x^2+x+5x=8\)
\(6x=8\)
\(x=8:6\)
\(x=\frac{4}{3}\)