Phân tích thành nhân tử ( bằng kĩ thuật tách hạng tử ):
6x^2 + 15x +6
6x^2 - 15x + 6
6x^2 + 20x + 6
6x^2 - 20x +6
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![](https://rs.olm.vn/images/avt/0.png?1311)
a. \(=6x^2-4x-9x+6=2x\left(3x-2\right)-3\left(3x-2\right)=\left(3x-2\right)\left(2x-3\right)\)
b. \(=6x^2+4x+9x+6=2x\left(3x+2\right)+3\left(3x+2\right)=\left(3x+2\right)\left(2x+3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(6x^2-15x+6\)
\(=6x^2-3x-12x+6\)
\(=3x\left(2x-1\right)-6\left(2x-1\right)\)
\(=\left(3x-6\right)\left(2x-1\right)\)
\(=3\left(x-2\right)\left(2x-1\right)\)
b) \(6x^2-20x+6\)
\(=6x^2-2x-18x+6\)
\(=2x\left(3x-1\right)-6\left(3x-1\right)\)
\(=\left(2x-6\right)\left(3x-1\right)\)
\(=2\left(x-3\right)\left(3x-1\right)\)
c) \(-10x^2-7x+6\)
\(=5x-10x^2+6-12x\)
\(=5x\left(1-2x\right)+6\left(1-2x\right)\)
\(=\left(5x+6\right)\left(1-2x\right)\)
d) \(10x^2-7x-12\)
\(=10x^2-15x+8x-12\)
\(=5x\left(2x-3\right)+4\left(2x-3\right)\)
\(=\left(5x+4\right)\left(2x-3\right)\)
1) 6x^2 - 15x + 6
= 6x^2 - 12x - 3x +6
= 6x (x - 2) - 3 (x - 2)
= (x - 2) (6x - 3)
= 3 (x - 2) (x - 1)
2) 6x^2 - 20x + 6
= 6x^2 - 18x - 2x + 6
= 6x (x - 3) - 2 (x - 3)
= (x - 3) (6x - 2)
= 2 (x - 3) (3x - 1)
3) -10x^2 - 7x + 6
= -10x^2 + 5x - 12x + 6
= 5x (1 - 2x) + 6 (1 - 2x)
= (1 - 2x) (5x + 6)
4) 10x^2 - 7x - 12
= 10x^2 - 15x + 8x - 12
= 5x (2x - 3) + 4 (2x - 3)
= (2x - 3) (5x + 4)
good luck !
![](https://rs.olm.vn/images/avt/0.png?1311)
\(6x^2+20x+6=6x^2+18x+2x+6\)
\(=6x\left(x+3\right)+2\left(x+3\right)\)
\(=\left(x+3\right)\left(6x+2\right)\)
\(=2\left(x+3\right)\left(3x+1\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1,3x^2+3x-6=3x^2-3x+6x-6=\left(3x^2-3x\right)+\left(6x-6\right)=3x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(3x+6\right)\)
\(2,6x^2-13x+6=6x^2-4x-9x+6=\left(6x^2-4x\right)-\left(9x-6\right)=2x\left(3x-2\right)-3\left(3x-2\right)=\left(3x-2\right)\left(2x-3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)3x2+7x-6
=3x2-2x+9x-6
=x(3x-2)+3(3x-2)
=(x+3)(3x-2)
b)8x2-2x-3
=8x2-6x+4x-3
=2x(4x-3)+(4x-3)
=(2x+1)(4x-3)
c)6x2-15x+6
=3(2x2-5x+2)
=3(2x2-x-4x+2)
=3[x(2x-1)-2(2x-1)]
=3(x-2)(2x-1)
d)10x2+7x-6
=10x2+12x-5x-6
=2x(5x+6)-(5x+6)
=(2x-1)(5x+6)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
6x^5+15x^4+20x^3+15x^2+6x+1
=3x^4(2x+1)+6x^3(2x+1)+7x^2(2x+1)+4x(2x+1)+(2x+1)
=(2x+1)(3x^4+6x^3+7x^2+4x+1)
=(2x+1)(3x^2(x^2+x+1)+3x(x^2+x+1)+(x^2+x+1)
=(2x+1)(x^2+x+1)(3x^2+3x+1)
![](https://rs.olm.vn/images/avt/0.png?1311)
a. = \(6x^2+3x+12x+6=3x\left(2x+1\right)+6\left(2x+1\right)=\left(2x+1\right)\left(3x+6\right)=3\left(2x+1\right)\left(x+2\right)\)
b. \(=6x^2-3x-12x+6=3x\left(2x-1\right)-6\left(2x-1\right)=3\left(2x-1\right)\left(x-2\right)\)
c. \(=6x^2+2x+18x+6=2x\left(3x+1\right)+6\left(3x+1\right)=\left(2x+6\right)\left(3x+1\right)=2\left(x+3\right)\left(3x+1\right)\)
d. \(=6x^2-2x-18x+6=2x\left(3x-1\right)-6\left(3x-1\right)=2\left(x-3\right)\left(3x-1\right)\)
(+) 6x^2 + 15x + 6 = 6x^2 + 12x + 3x + 6
= 6x ( x+ 2 ) + 3 ( x + 2)
= ( 6x + 3) ( x + 2 )
= 3 (2 x + 1 ) ( x + 2)
(+) 6x^2 - 15x + 6 = 6x^2 - 3x - 12x + 6
= 3x( 2x - 1 ) - 6 ( 2x - 1 )
= ( 3 x - 6 )( 2x - 1)
= 3 ( x- 2 ) (2x- 1)