1.
3/4 . x = 1
2 4/7 x = 9/8 - 0,125
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Bài 1:
\(\left(-0,125\right)\times7,9\times80\)
\(=\left(-0,9875\right)\times80\)
\(=79.\)
\(\left(0,125\right)\times1\times0,25\times8\times\left(-4\right)\)
\(=0,125\times0,25\times8\times\left(-4\right)\)
\(=0,03125\times8\times\left(-4\right)\)
\(=0,25\times\left(-4\right)\)
\(=\left(-1\right).\)
Bài 2:
\(x+\frac{8}{3}^2=\frac{1}{9}\)
\(x+16=\frac{1}{9}\)
\(x=\frac{1}{9}-16.MSC=9\)
\(x=\frac{1}{9}-\frac{144}{9}\)
\(x=\frac{-143}{9}.\)
a, \(\left(\dfrac{7}{2}-2x\right).\dfrac{10}{3}=\dfrac{22}{3}\Leftrightarrow\dfrac{7}{2}-2x=\dfrac{22}{10}=\dfrac{11}{5}\)
\(\Leftrightarrow2x=\dfrac{13}{10}\Leftrightarrow x=\dfrac{13}{20}\)
b, \(\dfrac{4x}{9}=\dfrac{9}{8}-\dfrac{125}{1000}=1\Leftrightarrow x=\dfrac{9}{4}\)
c, \(-\dfrac{x}{21}=\dfrac{60}{21}\Rightarrow x=-60\)
c: Ta có: \(\left|x+\dfrac{5}{6}\right|:\dfrac{4}{5}=\dfrac{3}{8}\)
\(\Leftrightarrow\left|x+\dfrac{5}{6}\right|=\dfrac{3}{8}\cdot\dfrac{4}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{5}{6}=\dfrac{3}{10}\\x+\dfrac{5}{6}=-\dfrac{3}{10}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-8}{15}\\x=-\dfrac{17}{15}\end{matrix}\right.\)
\(\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\left(\dfrac{1}{8}=0,125\right)\)
\(\dfrac{4}{7}x=1\)
->x=1:\(\dfrac{4}{7}\)
-> x= \(\dfrac{7}{4}\)
Ta có: \(\dfrac{4}{7}x=\dfrac{9}{8}-0.125\)
\(\Leftrightarrow\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}=1\)
hay \(x=\dfrac{7}{4}\)
Vậy: \(x=\dfrac{7}{4}\)
a)\(\frac{3}{4}\cdot x=1\)
\(x=1:\frac{3}{4}=\frac{4}{3}\)
b) \(2\frac{4}{7}\cdot x=\frac{9}{8}-0,125\)
\(\frac{18}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{18}{7}\cdot x=1\)
\(x=1:\frac{18}{7}=\frac{7}{18}\)