A = 4047991- 2010 . 2009 / 4050000 - 2011 . 2009
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{4047991-2010.2009}{4050000-2011.2009}\)
\(\Rightarrow A=\frac{404791-2010.2009}{4047911+2009-2011.2009}\)
\(\Rightarrow A=\frac{4047911-2010.2009}{4047911-2010.2009}\)
\(\Rightarrow A=1\)
Vậy A = 1
~Study well~
#๖ۣۜNamiko#
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{4047991-2010\times2009}{4050000-2011\times2009}=\frac{4047991+2009-2009-2010\times2009}{4050000-2011\times2009}\)
\(=\frac{4050000-2011\times2009}{4050000-2011\times2009}=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Dễ thấy:
\(\frac{2008}{2009}>\frac{2008}{2009+2010+2011}\)
\(\frac{2009}{2010}>\frac{2009}{2009+2010+2011}\)
\(\frac{2010}{2011}>\frac{2010}{2009+2010+2011}\)
=>\(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)
Hay \(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008+2009+2010}{2009+2010+2011}\)
Vậy A > B
![](https://rs.olm.vn/images/avt/0.png?1311)
A = \(\dfrac{2008}{2009+2010+2011}+\dfrac{2009}{2009+2010+2011}+\dfrac{2010}{2009+2010+2011}\)
Ta có:
\(\dfrac{2008}{2009}>\dfrac{2008}{2009+2010+2011}\)
\(\dfrac{2009}{2010}>\dfrac{2009}{2009+2010+2011}\)
\(\dfrac{2010}{2011}>\dfrac{2010}{2009+2010+2011}\)
Từ 3 điều trên suy ra : A < B
4047991- 2010 . 2009 / 4050000 - 2011 . 2009
=9901/9901
=1